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2 years ago

A cheetah goes from 0 m/s to 25 m/s in 2.5s. what is the cheetahs rate of acceleration? A. 10m/s2

Physics

1 answer:

OleMash [197]2 years ago

5 0

The cheetah's rate of acceleration is 10 m/s².Option A is correct.

<h3>What is acceleration?</h3>

The rate of velocity change concerning time is known as acceleration.

Given data;

Initial velocity, u= 0 m/s

Final velocity, v= 25 m/s

Time elapsed, t = 2.5 seconds.

To find ;

Acceleration, a

The acceleration when the change in velocity is observed by the formula as:

$\rm a= \frac{v-u}{t}$

Substitute the given values:

$\rm a= \frac{25-0}{2.5} \\\\ a= 10 \ m/s^2$

The cheetah's rate of acceleration is 10 m/s²

Hence option A is correct.

To learn more about acceleration, refer to the link brainly.com/question/2437624

#SPJ1.

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Answer:

force becomes one - ninth

Explanation:

According to Coulomb's law in electrostatics, two charges can exert a force of attraction or repulsion on each other which is directly proportional to the product of two charges and inversely proportional to the square of distance between them.

Here both the charges remains same but the distance is variable.

So, we can say that

$F \alpha \frac{1}{d^{2}}$ .... (1)

Where d be the distance between the tow charges

As the distance between two charges increases by factor of three, let the new force be F'.

$F' \alpha \frac{1}{9d^{2}}$ .... (2)

Divide equation (2) by equation (1), we get

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3 years ago

A pendulum consists of a large balanced mass hanging on the end of a long wire. At the point where a 28-kg pendulum has the grea

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Answer:

The length of the wire is approximately 67.1 m

Explanation:

The parameters of the pendulum are;

The mass of the pendulum, m = 28 kg

The angle between the pendulum weight and the wire, θ = 89°

The magnitude of the torque exerted by the pendulum's weight, τ = 1.84 × 10⁴ N·m

We have;

Torque, τ = F·L·sinθ = m·g·l·sinθ

Where;

F = The applies force = The weight of the pendulum = m·g

g = The acceleration due to gravity ≈ 9.8 m/s²

l = The length of the wire

Plugging in the values of the variables gives;

1.84 × 10⁴ N·m = 28 kg × 9.8 m/s² × l × sin(89°)

Therefore;

l = 1.84 × 10⁴ N·m/(28 kg × 9.8 m/s² × sin(89°)) = 67.0656080029 m ≈ 67.1 m

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3 years ago

Let’s tie this all together. It makes sense that, if the rope force remains greater than the gravitational force, the child keep

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Answer:

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If tension force is less than the weight then child will decelerate and his speed will decrease

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