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natita [175]
2 years ago
8

Bodies A and B have equal mass. Body B is initially at rest. Body A collides with body B in a one–dimensional elastic collision.

Which statement is true?
Body A comes to rest.

The momentum of the system is not conserved.
The kinetic energy of the system is not conserved.
The final velocity of body B is twice the initial velocity of body A.
Physics
2 answers:
adell [148]2 years ago
8 0
Body A comes to the rest as this criteria can only conserve the momentum .. keep one thing in mind velocities get exchanged when there is a perfect elastic collision that to the masses have to be same
Luden [163]2 years ago
5 0

Answer:

Body A comes to rest.

Explanation:

If two objects collide and one of them was at rest and have the same mass, what will happen is that the one that was at rest will absorbe the kinetic energy of the system, and start moving with the same initial velocity of Body A.

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A paintball’s mass is 0.0032kg. A typical paintball strikes a target moving at 85.3 m/s.
vekshin1

Answer:

A)  If the paintball stops completely the magnitude of the change in the paintball’s momentum is  p=0.273kg*m/s

B) If the paintball bounces off its target and afterward moves in the opposite direction with the same speed, the change in the paintball’s momentum is  p=0.546kg*m/s

C) A paintball bouncing off your skin in the opposite direction with the same speed hurts more than a paintball exploding upon your skin because of the strength exerted is twice than if it explodes.

Explanation:

Hi

A) We use the formula of momentum p=mv, so we have p=0.0032kg*85.3m/s=0.273kg*m/s

B) We use the same formula above, then due we have a change of direction at the same speed, therefore the change in the momentum is the double so

p=2*0.0032kg*85.3m/s=0.546kg*m/s.

C) The average strength of the force an object exerts during impact is determined by the amount the object’s momentum changes. therefore

F=\frac{\Delta p}{\Delta t}, as we don't have any data about the impact time but we know momentum is twice, time does no matter and strength is twice too.

4 0
3 years ago
A typical meteor that hits the earth's upper atmosphere has a mass of only 2.5 g, about the same as a penny, but it is moving at
attashe74 [19]

Answer:

Answer:u=66.67 m/s

Explanation:

Given

mass of meteor m=2.5 gm\approx 2.5\times 10^{-3} kg

velocity of meteor v=40km/s \approx 40000 m/s

Kinetic Energy of Meteor

K.E.=\frac{mv^2}{2}

K.E.=\frac{2.5\times 10^{-3}\times (4000)^2}{2}

K.E.=2\times 10^6 J

Kinetic Energy of Car

=\frac{1}{2}\times Mu^2

=\frac{1}{2}\times 900\times u^2

\frac{1}{2}\times 900\times u^2=2\times 10^6  

900\times u^2=4\times 10^6

u^2=\frac{4}{9}\times 10^4

u=\frac{2}{3}\times 10^2

u=66.67 m/s

8 0
2 years ago
by how many times occur in the force of attraction between two bodies change when the distance between then is reduced to one th
xenn [34]

Answer:

<em>The force is now 9 times the original force</em>

Explanation:

<u>Coulomb's Law </u>

The electrostatic force between two charged particles is directly proportional to the product of their charges and inversely proportional to the square of the distance between them.

Coulomb's formula is:

\displaystyle F=k\frac{q_1q_2}{d^2}

Where:

k=9\cdot 10^9\ N.m^2/c^2

q1, q2 = the particles' charge

d= The distance between the particles

Suppose the distance is reduced to d'=d/3, the new force F' is:

\displaystyle F'=k\frac{q_1q_2}{\left(\frac{d}{3}\right)^2}

\displaystyle F'=k\frac{q_1q_2}{\frac{d^2}{9}}

\displaystyle F'=9k\frac{q_1q_2}{d^2}

\displaystyle F'=9F

The force is now 9 times the original force

8 0
2 years ago
What is the charge of the negative sphere
tatyana61 [14]

Answer:

electrons

Explanation:

8 0
2 years ago
Ezekiel pushes a 34 kg sled with 101 N for 8.0 m. How much work did he do on the sled?
Simora [160]

Answer: 810 J

Explanation: work W = F·s = 101 N · 8.0 m = 808 J

Force F = u mg = 101 N in which u is friction constant. Also mass is included in force.

7 0
2 years ago
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