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2 years ago

5

Two point charges exert a 5.00 N force on each other. What will the force become if the distance between them is increased by a

factor of three?

1 answer:

weeeeeb [17]2 years ago

6 0

Answer:

force becomes one - ninth

Explanation:

According to Coulomb's law in electrostatics, two charges can exert a force of attraction or repulsion on each other which is directly proportional to the product of two charges and inversely proportional to the square of distance between them.

Here both the charges remains same but the distance is variable.

So, we can say that

$F \alpha \frac{1}{d^{2}}$ .... (1)

Where d be the distance between the tow charges

As the distance between two charges increases by factor of three, let the new force be F'.

$F' \alpha \frac{1}{9d^{2}}$ .... (2)

Divide equation (2) by equation (1), we get

$\frac{F'}{F}=\frac{d^{2}}{9d^{2}}$

$F'=\frac{F}{9}$

Thus, the force becomes one - ninth times the initial force.

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Answer:

$4.7\mu m$

Explanation:

We are given that

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We know that

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Where

$\epsilon_0=8.85\times 10^{-12}C^2/Nm^2$

Using the formula

$d=\frac{8.85\times 10^{-12}\times 154}{29\times 10^{-5}}$

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Using $1\mu m=10^{-6} m$

Hence, the spacing between the plates= $4.7\mu m$

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3 years ago

A weight lifter lifts a 345 N set of weights from ground level to a position over his head, a vertical distance of 1.89 m. How m

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Explanation:

Given

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An electron is released from rest on the axis of a uniform positively charged ring, 0.200 m from the ring's center. If the linea

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Answer:

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Explanation:

<u>Given:</u>

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Potential due the ring at a distance x from the centre of the rings is given by

$V=\dfrac{kQ}{\sqrt{(R^2+x^2)}}\\$

The potential difference when the electron moves from x=0.2 m to the centre of the ring is given by

$\Delta V=\dfrac{kQ}{R}-\dfrac{kQ}{\sqrt{(R^2+x^2)}}\\\Delta V={9\times10^9\times0.251\times10^{-6}} \left( \dfrac{1}{0.4}-\dfrac{1}{\sqrt{(0.4^2+0.2^2)}} \right )\\\Delta V=5.12\times10^2\ \rm V$

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Change in Potential Energy of the electron will be equal to the change in kinetic Energy of the electron

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Answer:

Explanation:

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Answer:

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Explanation:

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