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Viefleur [7K]
1 year ago
6

. Find the magnitude of the force between two charges, where the first charge is -2µc and the second charge is 3.5µc separated b

y distance of 15 cm in air. Also, define the nature of the force.​
Physics
1 answer:
Art [367]1 year ago
3 0

Answer:  The relationship between changing magnetic flux and induced electromotive force is known as Faraday's law of electromagnetic induction: The magnitude of an electromagnetic force induced in a circuit is proportional to the rate of change of the magnetic flux that cuts across the circuit.

Explanation:

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An 80 kg object has a µk = 0.35 and a µs = 0.60. Assuming it is on a flat surface
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Answer:

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How much force is required to get the object to start to move from rest (max static friction)?

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Explanation:

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3 years ago
What is the resistance of a 1.3-m-long copper wire that is 0.30 mm in diameter?
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The resistance R of a wire is given by:
R= \frac{\rho L}{A}
where 
\rho is the resistivity of the material
L is the length of the wire
A is the cross-sectional area of the wire.

For the wire in the problem, the resistivity is (copper resistivity) \rho=1.68 \cdot 10^{-8} \Omega m. The length of the wire is L=1.3 m, while the cross-sectional area is
A=\pi r^2 = \pi ( \frac{d}{2})^2 = \pi ( \frac{0.30 \cdot 10^{-3} m}{2} )^2 =7.07 \cdot 10^{-8} m^2

so the resistance of the wire is:
R= \frac{(1.68 \cdot 10^{-8} \Omega m)(1.3 m)}{7.07 \cdot 10^{-8} m^2}=0.31 \Omega
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3 years ago
Two equal mass carts approach each other with velocities equal in magnitude but opposite in direction. Friction can be neglected
Viefleur [7K]

Answer:

0

Explanation:

Since momentum is given by:

\vec{p}=m.\vec{v}

Therefore momentum is a vector quantity in the direction of velocity.

  • Inelastic collision is the type of collision in which the masses combine after collision and start moving in the direction of the greater momentum but here in this case we have the momentum equal and opposite in direction.

<u>This case can be described mathematically as:</u>

m_1.\vec{v_1}=m_2.\vec{v_2}

since the mass and velocity are equal:

m.\vec{v}=m.\vec{v}

net momentum:

p_{net}=0

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