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ale4655 [162]
2 years ago
7

How do chemicals affect our lives

Chemistry
1 answer:
Ivenika [448]2 years ago
4 0

As, the chemicals are toxic, they have adverse effects in our life.

<h3>What is chemical?</h3>

A compound or element which reacts with the other element to form a product.

Chemicals are generally toxic because they harm our skin, when they come in contact with the body. When exposed to a toxic substance,  gasoline can affect your health. Since, drinking gasoline can cause burns, vomiting, diarrhea and can cause death,

Thus, the chemicals are toxic.

Learn more about chemical.

brainly.com/question/13145357

#SPJ1

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If the amount of energy required to break bonds in the reactants is more than the amount of energy released in forming bonds in
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Answer:

YASSSSSSS

Explanation:

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If 2.40 moles of gas are held at a temperature of 97.0 °C in a container with a volume of 45.0 L, what is the pressure of the ga
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PV=nRT<=> P=nRT/V=2,40*R*(273+97)/45 atm.
Calculate it. R is a number that is given, find it and use your math to solve.
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Why noble gas neon is an unreactive element?
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3 years ago
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The reaction of 2-methylbutane with chlorine would yield how many monochloro derivatives (include stereoisomers)?
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The ksp of calcium carbonate, caco3, is 3.36 × 10-9 m2. calculate the solubility of this compound in g/l.
maw [93]
CaCO₃ partially dissociates in water as Ca²⁺ and CO₃²⁻. The balanced equation is,
                       CaCO₃(s) ⇄ Ca²⁺(aq) + CO₃²⁻(aq)
Initial                Y                   -                 -
Change           -X                  +X              +X
Equilibrium      Y-X                 X                X

Ksp for the CaCO₃(s) is 3.36 x 10⁻⁹ M²

                Ksp = [Ca²⁺(aq)][CO₃²⁻(aq)]
3.36 x 10⁻⁹ M² = X * X
3.36 x 10⁻⁹ M² = X²
                    X = 5.79 x 10⁻⁵ M

Hence the solubility of CaCO₃(s) = 5.79 x 10⁻⁵ M
                                                     = 5.79 x 10⁻⁵ mol/L

Molar mass of CaCO₃ = 100 g mol⁻¹

Hence the solubility of CaCO₃ = 5.79 x 10⁻⁵ mol/L x 100 g mol⁻¹
                                                 = 5.79 x 10⁻³ g/L

7 0
3 years ago
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