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Vlad [161]
3 years ago
9

At what temperature will 2.40 moles of chlorine gas exert a pressure of 2.70 atm at a volume of 0.750 L?

Chemistry
2 answers:
Kamila [148]3 years ago
8 0

Answer:

—262.71°C

Explanation:

Step 1:

The following data were obtained from the question:

Number of mole (n) = 2.4 moles

Pressure (P) = 2.70 atm

Volume (V) = 0.750 L

Temperature (T) =?

Gas constant (R) = 0.082atm.L/Kmol

Step 2:

Determination of the temperature.

Using the ideal gas equation, the temperature can be obtained as follow:

PV = nRT

2.7 x 0.750 = 2.4 x 0.082 x T

Divide both side by 2.4 x 0.082

T = (2.7 x 0.750) /(2.4 x 0.082)

T = 10.29K

Step 3:

Conversion of Kelvin temperature to celsius temperature.

Temperature (celsius) = temperature (Kelvin) - 273

temperature (Kelvin) = 10.29K

Temperature (celsius) = 10.29 - 273

Temperature (celsius) = —262.71°C

DochEvi [55]3 years ago
6 0

Answer:

10.28Kelvin

Explanation:

Using the ideal gas equation;

PV = nRT

P is the pressure

V is the volume of the gas

n is the number of moles

T is the temperature in Kelvin

R is the Gas constant

Given n = 2.4moles

P = 2.70atm

V = 0.750L

R = 0.0821atm.L/mol.K

From the formula above:

T = PV/nR

T = 2.70×0.750/2.4×0.0821

T = 2.025/0.197

T = 10.28K

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Consider 2H2 + O2 → 2H2O. To produce 1.2 g water, how many grams of H2 are required? Report to the correct number of significant
Elden [556K]

Answer:

0.133 mol (corrected to 3 sig.fig)

Explanation:

Take the atomic mass of H=1.0, and O=16.0,

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Answer:

The equilibrium constant for the reversible reaction = 0.0164

Explanation:

At equilibrium the rate of forward reaction is equal to the rate of backwards reaction.

The reaction is given as

A ⇌ B

Rate of forward reaction is first order in [A] and the rate of backward reaction is also first order in [B]

The rate of forward reaction = |r₁| = k₁ [A]

The rate of backward reaction = |r₂| = k₂ [B]

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where k₁ and k₂ are the forward and backward rate constants respectively.

k₁ = 0.010 s⁻¹

k₂ = 0.0610 s⁻¹

|r₁| = 0.010 [A]

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At equilibrium, the rate of forward and backward reactions are equal

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