I would say B.HS(aq)+NiSO4(aq)
B) Accurate is the right answer
Answer: 67.23 L
Explanation:
According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number 
of particles.
To calculate the number of moles, we use the equation:
Putting in the values we get:
1 mole of methane occupies = 22.4 L
Thus 3 moles of methane occupy = 
Thus volume of 48 grams of methane gas is 67.23 L
Answer:
The new volume of the gas is decreased, to 0.329 L
Explanation:
Step 1: Data given
Volume of oxygen = 500 mL = 0.500 L
Pressure = 1.3 atm
Temperature = 25.0 °C
Temperature increases to 29.0 °C
New pressure = 2.0 atm
Step 2: Calculate new volume
p1*V1/T1 = p2*V2/T2
⇒with p1 = the initial pressure = 1.3 atm
⇒with V1 = the initial volume = 0.500L
⇒with T1 = the initial temperature = 25 °C = 298 K
⇒with p2 = the new pressure = 2.0 atm
⇒with V2 = the new volume = TO BE DETERMINED
⇒with T2 = the new temperature = 29 °C = 302 K
(1.3 * 0.500)/298 = (2.0 * V2) /302
0.0021812 = 2.0V2 / 302
V2 = 0.329 L = 329 mL
The new volume of the gas is decreased, to 0.329 L
