Hi i a doing the same thing and i have the answer as a hope this helps
put the equation 2x - y = 16 in the form of y = mx + c
2x - y = 16
2x = 16 + y
y = 2x - 16
the slope of this line is 2. the slope of a line perpendicular to it would be the negative reciprocal of 2. in other words, it would multiply with 2 to give -1.
you can form this equation with that info
2x = -1
x = -1/2
OR
you can flip and change the sign (numerator) of 2/1
2/1
= -1/2
Answer: ![(21.541,\ 23.059)](https://tex.z-dn.net/?f=%2821.541%2C%5C%2023.059%29)
Step-by-step explanation:
The confidence interval for population mean is given by :-
![\overline{x}\pm z_{\alpha/2}\dfrac{\sigma}{\sqrt{n}}](https://tex.z-dn.net/?f=%5Coverline%7Bx%7D%5Cpm%20z_%7B%5Calpha%2F2%7D%5Cdfrac%7B%5Csigma%7D%7B%5Csqrt%7Bn%7D%7D)
Given : Sample size :
, which is a large sample , so we apply z-test .
Sample mean : ![\overline{x}=22.3](https://tex.z-dn.net/?f=%5Coverline%7Bx%7D%3D22.3)
Standard deviation : ![\sigma= 6](https://tex.z-dn.net/?f=%5Csigma%3D%206)
Significance level : ![\alpha=1-0.95=0.05](https://tex.z-dn.net/?f=%5Calpha%3D1-0.95%3D0.05)
Critical value : ![z_{\alpha/2}=1.960](https://tex.z-dn.net/?f=z_%7B%5Calpha%2F2%7D%3D1.960)
Now, a confidence interval at the 95% level of confidence will be :-
![22.3\pm(1.960)\dfrac{6}{\sqrt{240}}\\\\\approx22.3\pm0.759\\\\=(22.3-0.759,\ 22.3+0.759)\\\\=(21.541,\ 23.059)](https://tex.z-dn.net/?f=22.3%5Cpm%281.960%29%5Cdfrac%7B6%7D%7B%5Csqrt%7B240%7D%7D%5C%5C%5C%5C%5Capprox22.3%5Cpm0.759%5C%5C%5C%5C%3D%2822.3-0.759%2C%5C%2022.3%2B0.759%29%5C%5C%5C%5C%3D%2821.541%2C%5C%2023.059%29)
i cant see the pic that good