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malfutka [58]
3 years ago
7

Please Help me on this question

Mathematics
2 answers:
stepladder [879]3 years ago
7 0
Its yellow hipe this helps
zlopas [31]3 years ago
6 0

Answer:

yellow

Step-by-step explanation:

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Help please?
ziro4ka [17]

Answer:

  • cos(θ) = -1/2
  • tan(θ) = √3

Step-by-step explanation:

You know that ...

  • cos(θ)² = 1 - sin(θ)²
  • tan(θ) = sin(θ)/cos(θ)
  • cosine is negative in the third quadrant (where π < θ < 3π/2)

Using what you know about the relationships of these trig functions, you can find ...

  cos(θ)² = 1 - ((-√3)/2)² = 1 - 3/4 = 1/4

  cos(θ) = -1/2 . . . . . negative square root of 1/4

__

  tan(θ) = sin(θ)/cos(θ) = ((-√3)/2)/(-1/2)

  tan(θ) = √3

8 0
3 years ago
Yooo someone
natita [175]

Answer:

39 sq cm

Step-by-step explanation:

Ok.  Since ΔAED is isosceles, then the height of the trapezoid is 3 cm

One base is 16 and the other base is 16 - 3 - 3 = 10.

A = 1/2 h(b_{1} + b_{2})  where b_{1} and b_{2} are lengths of the bases

A = 1/2(3)(10 + 16)

  = 1/2(3)(26)

  = 39 sq cm

8 0
3 years ago
Aiden picked 3/8 of the carrots in his garden. There were 32 carrots in his garden.
Ann [662]
The answer is 12 carrots:)
3 0
4 years ago
Read 2 more answers
What was the date of when the "Little Rock Nine" students entered a white public school?
Alika [10]

Answer: 1957

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
What is the value of the correlation coefficient r of the data set?
enyata [817]

The correct option will be:  C) 0.84

<u><em>Explanation</em></u>

Formula for Correlation coefficient :

r= \frac{n(\Sigma xy)-(\Sigma x)(\Sigma y)}{\sqrt{[n\Sigma x^2-(\Sigma x)^2][n\Sigma y^2-(\Sigma y)^2]}}

First, for each point(x, y), we need to calculate x², y² and xy .

Then, we will find sum all x, y, x², y² and xy, which gives us Σx, Σy, Σx², ∑y² and Σxy

<em>(Please refer to the attached image for the table )</em>

Here we got, ∑x = 44 , ∑y = 183 , ∑x² = 362 , ∑y² = 6575 and ∑xy = 1480

'n' is the total number of data set, which is 7 here.

So, plugging those values into the above formula..........

r= \frac{n(\Sigma xy)-(\Sigma x)(\Sigma y)}{\sqrt{[n\Sigma x^2-(\Sigma x)^2][n\Sigma y^2-(\Sigma y)^2]}}\\ \\ r=\frac{7(1480)-(44)(183)}{\sqrt{[7(362)-(44)^2][7(6575)-(183)^2]}}\\ \\ r=\frac{10360-8052}{\sqrt{(598)(12536)}}\\ \\ r=\frac{2308}{\sqrt{7496528}}\\ \\ r=0.84

So, the value of the correlation coefficient is 0.84

4 0
3 years ago
Read 2 more answers
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