Given:
t1 = 3.6 h
t2 = 4.5 h
x = speed of boat
y = speed of water
Required:
a) Expression of distance traveled with moving water with 3.6h
Expression of distance traveled with moving water with 4.5h
b) Solve for y
c) Percent of boat's speed is the water current
Solution:
Working formula: distance = velocity*time
a) For travelling downstream, we get the equation
d = (x +y)*3.6
For travelling upstream, we get the equation
d = (x-y)*4.5
b) Setting the distance as equal for travelling upstream or downstream, we arrive at the equation of
(x+y)*3.6 = (x-y)*4.5
3.6x + 3.6y = 4.5x - 4.5y
8.1y =0.9x
y = x/9
c) percentage = 1/9*100% = 11.1%
<em>ANSWERS: a) d = (x+y)*36; d = (x-y)*4.5
</em> <em>b) y = x/9
</em> <em>c) 11.1%</em>
Answer:
726.572699
Step-by-step explanation:
According to differentials
(x+Δx)³ = x³ + 3x²Δx + 3x(Δx)² + (Δx)³ (Using binomial expansion)
Using this formula to solve (8.99)³, this can also be written as;
(8.99)³ = (9-0.01)³ where
x = 9
Δx = -0.01
Substitute this vales into the differential expression above
(9+(-0.01))³ = 9³ + 3(9)²(-0.01) + 3(9)(-0.01)² + (-0.01)³
(9+(-0.01))³ = 729 + (243)(-0.01) + 27(0.0001) + (-0.000001)
(9+(-0.01))³ = 729-2.43+0.0027-0.000001
(9+(-0.01))³ = 729-2.43+0.0027-0.000001
(9+(-0.01))³ = 726.572699
Hence 8.99³ = 726.572699 (Using differential)
Using calculator;
8.99³ = 726.572699
The polynomial is 3x^2 + 10x + 3 and the two factors are (3x+1) and (x+3), because
(3x+1)(x+3) = 3x^2 +9x + x +3 = 3x^2 + 10x +3
Answer:
mean but im guessing as well
Step-by-step explanation:
