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3 years ago

14

for his phone service carlos pays a monthly fee of $19 and he pays an additional $0.07 per minute of use the lease has been char

ging a month is $97.75 what are the possible numbers of minutes he has used his phone in a month?

1 answer:

Lostsunrise [7]3 years ago

4 0

first you should try to find the closest multiple of 19 which you should multiply 19 by 5 and get 95. then subtract 97.75-95 which equals 2.75. 2.75 then needs to be divided by the cost per extra minute 0.07 so 2.75 divided by .07 which gets you 39. 39 minutes

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Which algebraic expression represents this phrase?

Westkost [7]

The word "product" means <em>multiplication </em>

that means the answer is

40 · d

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3 years ago

B(n)=-8-2(n-1)<br> Find the 9th term

TEA [102]

Answer:

The 9th term will be -24

Step-by-step explanation:

The 9th term will be equal to

$b_{n}$ = - 8 - 2(n - 1)

$b_{9}$ = - 8 - 2(9 - 1)

$b_{9}$ = - 8 - 18 + 2

$b_{9}$ = - 24

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3 years ago

Consider the following function. f(x) = 16 − x2/3 Find f(−64) and f(64). f(−64) = f(64) = Find all values c in (−64, 64) such th

VARVARA [1.3K]

Answer:

This does not contradict Rolle's Theorem, since f '(0) = 0, and 0 is in the interval (−64, 64).

Step-by-step explanation:

The given function is

$f(x)=16-\frac{x^2}{3}$

To find $f(-64)$ , we substitute $x=-64$ into the function.

$f(-64)=16-\frac{(-64)^2}{3}$

$f(-64)=16-\frac{4096}{3}$

$f(-64)=-\frac{4048}{3}$

To find $f(64)$ , we substitute $x=64$ into the function.

$f(64)=16-\frac{(64)^2}{3}$

$f(64)=16-\frac{4096}{3}$

$f(64)=-\frac{4048}{3}$

To find $f'(c)$ , we must first find $f'(x)$ .

$f'(x)=-\frac{2x}{3}$

This implies that;

$f'(c)=-\frac{2c}{3}$

$f'(c)=0$

$\Rightarrow -\frac{2c}{3}=0$

$\Rightarrow -\frac{2c}{3}\times -\frac{3}{2}=0\times -\frac{3}{2}$

$c=0$

For this function to satisfy the Rolle's Theorem;

It must be continuous on $[-64,64]$ .

It must be differentiable on $(-64,64)$ .

and

$f(-64)=f(64)$ .

All the hypotheses are met, hence this does not contradict Rolle's Theorem, since f '(0) = 0, and 0 is in the interval (−64, 64) is the correct choice.

6 0

3 years ago

Read 2 more answers

Pleasee help me guyss .

Setler79 [48]

Answer:

24%

Step-by-step explanation:

25 - 19 = 6

25 = 100%

2.5 = 10%

1.25 = 5%

0.25 = 1%

5 = 20%

1 = 4%

6 = 24%

Hope this helps :)

3 0

3 years ago

Read 2 more answers

a fruit delivers its fruit in two types of boxes: large and small. a delivery of 3 large boxes and 5 small boxes has a total wei

Masteriza [31]

Answer:

The weight of a small box = 13.5 kg

The weight of 1 large box = 18.5 kg

Step-by-step explanation:

Let us assume the weight of a small box = m kg

And the weight of 1 large box = n kg

Now, the weight of 5 small box = 5 x (weight of 1 small box) = 5 m

Also, the weight of 3 large box = 3 x (weight of 1 large box) = 3 n

Here, 3 large boxes + 5 small boxes = of 123 kilograms

⇒ 5 m + 3 n = 123 .... (1)

Again, the weight of 2 small box = 2 x (weight of 1 small box) = 2 m

Also, the weight of 12 large box = 12 x (weight of 1 large box) = 12 n

Here, 12 large boxes + 2 small boxes = 249 kilograms

⇒ 2 m+ 12 n = 249 .... (2)

Now, solving both the given equations by ELIMINATION, we get:

5 m + 3 n = 123 x (2)

2 m+ 12 n = 249 x (-5)

we get the new set of equitation as:

10 m + 6 n = 246

- 10 m - 60 n = -1245

Adding both equation, we get

-54 n = 999

or, n = 18.5

Now, 5 m + 3 n = 123

So, 5 m = 123 -3 (18.5) = 123 - 55.5 = 67.5

⇒ m = 13.5

Hence, the weight of a small box = m kg = 13.5 kg

And the weight of 1 large box = n kg = 18.5 kg

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3 years ago