This is a build up of lava which came out of the volcano in previous eruptions, once this lava came out of the volcano it cooled and hardened, over many eruptions layers of hardened volcanic rock will form. The layers are slanted as gravity acts on the lava so it flows down and a little further from the cone.
Answer:
El yoduro de potasio es una sal cristalina de fórmula KI, usada en fotografía y tratamiento por radiación. Al ser menos higroscópica que el yoduro de sodio, es más utilizada como fuente de ion yoduro.
Explanation:Se porta como una sal simple. El ion yoduro, al ser un reductor débil, es fácilmente oxidado por otros elementos como el cloro para transformarse en yodo:
2 KI(ac) + Cl2(ac) → 2 KCl + I2(ac)
Tiene un pH neutro (pH = 7) ya que el catión potasio y el anión yoduro son iones espectadores, por lo que no reaccionan con el agua, manteniéndose inalterado el pH. El yoduro se oxida aún más fácilmente al formar ácido yodhídrico (HI), el cual es un reductor más fuerte que el KI. El yoduro de potasio forma el anión triyoduro(I3−) al combinarse con yodo elemental.
A diferencia del yodo, los triyoduros son altamente solubles en agua, por lo que el yoduro de potasio aumenta considerablemente la solubilidad del yodo elemental en agua, que por sí solo se disuelve en muy bajas cantidades.
Answer:
Option b.) Potassium ion, is written correctly.
Explanation:
Hope this helps! :)
Answer:
2.05*10⁻⁵ moles of CF₂ can dissolve in 100 g of water.
12.82 moles of CaF₂ will dissolve in exactly 1.00 L of solution
Explanation:
First, by definition of solubility, in 100 g of water there are 0.0016 g of CaF₂. So, to know how many moles are 0.0016 g, you must know the molar mass of the compound. For that you know:
- Ca: 40 g/mole
- F: 19 g/mole
So the molar mass of CaF₂ is:
CaF₂= 40 g/mole + 2*19 g/mole= 78 g/mole
Now you can apply the following rule of three: if there are 78 grams of CaF₂ in 1 mole, in 0.0016 grams of the compound how many moles are there?
moles=2.05*10⁻⁵
<u><em>2.05*10⁻⁵ moles of CF₂ can dissolve in 100 g of water.</em></u>
Now, to answer the following question, you can apply the following rule of three: if by definition of density in 1 mL there is 1 g of CaF₂, in 1000 mL (where 1L = 1000mL) how much mass of the compound is there?
mass of CaF₂= 1000 g
Now you can apply the following rule of three: if there are 78 grams of CaF₂ in 1 mole, in 1000 grams of the compound how many moles are there?
moles=12.82
<u><em>12.82 moles of CaF₂ will dissolve in exactly 1.00 L of solution</em></u>
