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Evgen [1.6K]
2 years ago
5

Question 7

Chemistry
1 answer:
Law Incorporation [45]2 years ago
3 0

Answer:

84.3 g of nitrogen triiodide is the theoretical yield.

Explanation:

Hello there!

In this case, according to the chemical reaction:

N_2 + 3I_2 \rightarrow 2NI_3

It is possible to compute the theoretical yield of nitrogen triiodide by each reactant via stoichiometry as shown below:

m_{NI_3}^{by\ N_2}=4.49gN_2*\frac{1molN_2}{28.01gN_2} *\frac{2molNI_3}{1molN_2}*\frac{394.72gNI_3}{1molNI_3}  =126.55gNI_3\\\\m_{NI_3}^{by\ I_2}=81.3gI_2*\frac{1molI_2}{253.81gI_2} *\frac{2molNI_3}{3molI_2}*\frac{394.72gNI_3}{1molNI_3}  =84.29gNI_3

Therefore, we infer that the smallest amount is the correct theoretical yield as it comes from the limiting reactant, in this case, diatomic iodine as it yields 84.3 g (three significant figures) of nitrogen triiodide as the theoretical yield; incidentally, nitrogen acts as the excess reactant.

Best regards!

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The number of C atoms in 0.524 moles of C is 3.15 atoms.

The number of SO_2 molecules in 9.87 moles  SO_2 is 59.43 molecules.

The moles of Fe in 1.40 x 10^{22} atoms of Fe is 0.23 x 10^{-1}

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<h3>What are moles?</h3>

A mole is defined as 6.02214076 × 10^{23} of some chemical unit, be it atoms, molecules, ions, or others. The mole is a convenient unit to use because of the great number of atoms, molecules, or others in any substance.

A. The number of C atoms in 0.524 mole of C:

6.02214076 × 10^{23} x 0.524 mole

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B. The number of SO_2 molecules in 9.87 moles of SO_2:

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C. The moles of Fe in 1.40 x 10^{22} atoms of Fe:

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D. The moles of C_2H_6O in 2.30x10^{24} molecules of C_2H_6O:

2.30x10^{24} ÷ 6.02214076 × 10^{23}

3.819239854 moles=3.81 moles

Learn more about moles here:

brainly.com/question/8455949

#SPJ1

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key words :

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