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2 years ago

Question 7

Chemistry

1 answer:

Law Incorporation [45]2 years ago

3 0

Answer:

84.3 g of nitrogen triiodide is the theoretical yield.

Explanation:

Hello there!

In this case, according to the chemical reaction:

$N_2 + 3I_2 \rightarrow 2NI_3$

It is possible to compute the theoretical yield of nitrogen triiodide by each reactant via stoichiometry as shown below:

$m_{NI_3}^{by\ N_2}=4.49gN_2*\frac{1molN_2}{28.01gN_2} *\frac{2molNI_3}{1molN_2}*\frac{394.72gNI_3}{1molNI_3} =126.55gNI_3\\\\m_{NI_3}^{by\ I_2}=81.3gI_2*\frac{1molI_2}{253.81gI_2} *\frac{2molNI_3}{3molI_2}*\frac{394.72gNI_3}{1molNI_3} =84.29gNI_3$

Therefore, we infer that the smallest amount is the correct theoretical yield as it comes from the limiting reactant, in this case, diatomic iodine as it yields 84.3 g (three significant figures) of nitrogen triiodide as the theoretical yield; incidentally, nitrogen acts as the excess reactant.

Best regards!

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How many atoms of N are in 137.0 grams of N2O3?

valina [46]

Answer:

1.085 x 10²⁴

Explanation:

The answer is not in your choices, but it maybe due to a typo but to get the answer to this, you just need to convert the grams to moles, then moles to atoms.

First we get the mass of the molecule for every mole. Get the atomic mass of each element and multiply it by the number of atoms present then get their total.

N₂O₃

Element number of atoms Atomic mass TOTAL

N 2 x 14.007 28.014

O 3 x 15.999 <u>47.997</u>

76.011 g/mole

So now we know for every 1 mole of N₂O₃ there are 76.011 g of N₂O₃.

Next we need to see how many moles of N₂O₃ are there in 137.0g of N₂O₃.

$137.0g\times\dfrac{1mole}{76.011g}=1.802moles$

Now we know that we have 1.802moles of N₂O₃.

We use Avogadro's constant to find out how many atoms there are. Avogadro's constant states that for every mole of any substance, there are 6.022140857 × 10²³ atoms.

$1.802moles\times\dfrac{6.022140857\times10^{23}atoms}{1 mole}=1.085\times10^{24}atoms$

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2 years ago

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D. Light energy is the right answer

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3 years ago

What is the density of a substance that has a volume of 14 millimeters and a mass of 13.2 grams.

Contact [7]

Answer:

Explanation:

The density of a substance can be found by using the formula

$density = \frac{mass}{volume} \\$

From the question we have

$density = \frac{13.2}{14} \\ = 0.94285...$

We have the final answer as

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2 years ago

600.0 mL of air is at 20.0 Celsius. What is the volume of the same air at 60.0 Celsius

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Answer:

0.682L or 682mL

Use Charles Law of V1/T1 = V2/T2

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Explanation:

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2 years ago

Is 2 KNO₃ + H₂CO₃ → K₂CO₃ + 4 HNO₃ a balanced equation

krok68 [10]

Hey there!

The elements in this equation are K, N, O, H, and C.

Let's count how many of each are on each side to see if it is balanced.

K: 2 on the left, 2 on the right.

<em>N: 2 on the left, 4 on the right. </em>

<em>O: 9 on the left, 6 on the right. </em>

<em>H: 2 on the left, 4 on the right. </em>

C: 1 on the left, 1 on the right.

Notice that there are different amounts of N, O, and H on the left side and the right side.

This means that the equation is not balanced.

Hope this helps!

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2 years ago