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AysviL [449]
2 years ago
14

What is oxidized and what is reduced in this reaction? cu(s) 2agno3(aq) → cu(no3)2(aq) 2ag(s) cu is reduced and ag is oxidized.

ag is reduced and cu is oxidized. no3 is oxidized and cu is reduced. ag is oxidized and no3 is reduced.
Chemistry
1 answer:
Luden [163]2 years ago
6 0

From the  reaction equation,  Cu is oxidized in the reaction while Ag is reduced.

<h3>What is a redox reaction?</h3>

The term redox reaction has to do with a reaction in which a specie is oxidized and another is reduced.

Here the reaction equation is; Cu(s) + 2AgNO3(aq) → Cu(NO3)2(aq) 2Ag(s) Cu. We can see that Cu is oxidized in the reaction while Ag is reduced.

Learn more about reaction: brainly.com/question/17434463

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1) If the pressure on 2.6 liters of a gas at 860 Torr is increased to 1000 Torr,
LenKa [72]

2.24 liters is the volume of the gas if pressure is increased to 1000 Torr.

Explanation:

Data given:

Initial volume of the gas V1 = 2.6 liters

Initial pressure of the gas P1 = 860 Torr 1.13 atm

final pressure on the gas P2 = 1000 Torr 1.315 atm

final volume of the gas after pressure change V2 =?

From the data given above, the law used is :

Boyles Law equation:

P1V1 = P2V2

V2 = P1V1/P2

   = 1.13 X 2.6/ 1.31

  = 2.24 Liters

If the pressure is increased to 1000 Torr or 1.315 atm the volume changes to 2.24 liters. Initially the volume was 2.6 litres and the pressure was 860 torr.

6 0
3 years ago
Give an explanation of how an electrical current is produced
Julli [10]

\huge\underline{ \overline{ \underline{ \bf{your \: answer}}}}

Electric current can be generated by moving a metal wire through a magnetic field. It is also different than static electricity, which is the accumulation of charges on a surface. <u>Electric generators rotate a coil</u> of wires through a magnetic field.

8 0
3 years ago
Read 2 more answers
Please help !!
ipn [44]

<u>Answer:</u>

<u>For 2:</u> The % yield of the product is 92.34 %

<u>For 3:</u> 12.208 L of carbon dioxide will be formed.

<u>Explanation:</u>

  • <u>For 2:</u>

The percent yield of a reaction is calculated by using an equation:

\% \text{yield}=\frac{\text{Actual value}}{\text{Theoretical value}}\times 100              ......(1)

Given values:

Actual value of the product = 78.4 g

Theoretical value of the product = 84.9 g

Plugging values in equation 1:

\% \text{yield}=\frac{78.4 g}{84.9g}\times 100\\\\\% \text{yield}=92.34\%

Hence, the % yield of the product is 92.34 %

  • <u>For 3:</u>

The number of moles is defined as the ratio of the mass of a substance to its molar mass.

The equation used is:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}} ......(2)

Given mass of carbon dioxide = 24 g

Molar mass of carbon dioxide = 44 g/mol

Plugging values in equation 1:

\text{Moles of carbon dioxide}=\frac{24g}{44g/mol}=0.545 mol

<u>At STP conditions:</u>

1 mole of a gas occupies 22.4 L of volume

So, 0.545 moles of carbon dioxide will occupy = \frac{22.4L}{1mol}\times 0.545mol=12.208L of volume

Hence, 12.208 L of carbon dioxide will be formed.

5 0
3 years ago
Find the mass in grams of 1.55 x 1023 molecules of Cl2?
forsale [732]
We are told that there are 1.55 x 10²³ molecules of Cl₂ and we need to calculate the mass of these molecules. We need to do several conversions. The easiest will be to convert the amount of molecules to the number of moles present. To do this, we need to use Avogadro's number which is 6.022 x 10²³ molecules/mole.

1.55 x 10²³ molecules / 6.022 x 10²³ molecules/mole = 0.257 moles Cl₂

Now that we have the moles of Cl₂ present, we can convert this value to a mass of Cl₂ by using the molecular mass of Cl₂. The molecular mass is 70.906 g/mol.

0.257 moles Cl₂ x 70.906 g/mol = 18.3 g Cl₂

Therefore, 1.55 x 10²³ molecules of Cl₂ will have a mass of 18.3 g.
7 0
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Density equals what?
Schach [20]

Answer:

Not exactly sure what you mean by this, but "The average density of an object equals its total mass divided by its total volume."

Explanation:

Hope this helps!

3 0
3 years ago
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