<u>Answer:</u>
<em>Latest take an example to understand how </em><em>balancing of chemical reaction</em><em> is done that is assuming the reaction between iron as well as </em><em>oxygen which reacts to form rust.</em>
<u>Explanation:</u>
For this we would simply right the reactant and product that is expected. Then we would see the number of molecules of each element present on either side.
If in the reaction the element’s molecules are the same on both sides then the reaction would be correct and if not then we have to apply trial and error method to balance the equation such that the number of molecules of each element is equal on both sides of the reaction.
Answer:
Theoretical yield of the reaction is 121·38 g
The excess reactant is hydrogen
The limiting reactant is nitrogen
Explanation:
By assuming that the reaction between nitrogen and hydrogen taking place in presence of catalyst because at normal conditions the reaction between them will not occur
Number of moles of nitrogen taken are 100÷28 ≈ 3.57
Number of moles of hydrogen taken are 100÷2 = 50
Actually the reaction between nitrogen and hydrogen takes place according to the following equation
<h3>N

+ 3H

→ 2NH

</h3>
So from the equation for 1 mole of nitrogen and 3 moles of hydrogen we get 2 moles of ammonia
Here in the problem we have approximately 3·57 moles of nitrogen so we require 3×3·57 moles of hydrogen
∴ Number of moles of hydrogen required is 10·71
But we have 50 moles of hydrogen
∴ Excess reagent is hydrogen and limiting reagent is nitrogen
Number of moles of ammonia produced is 2×3·57 = 7·14
Weight of ammonia is 17 g
∴ Amount of ammonia produced is 17×7·14 = 121·38 g
∴ Theoretical yield of the reaction is 121·38 g
Answer:
true
Explanation:
Because ice melts if the temperature increasese
Question 5 is the second one.
Answer:
The mass of this 25 mL supercritical CO2 sample has a mass of 11.7g
Explanation:
Step 1: Given data
The supercritical CO2 has a density of 0.469 g/cm³ (or 0.469 g/mL)
The sample hasa volume of 25.0 mL
Step 2: Calculating mass of the sample
The density is the mass per amount of volume
0.469g/cm³ = 0.469g/ml
The mass for a sample of 25.0 mL = 0.469g/mL * 25.0 mL = 11.725g ≈ 11.7g
The mass of this 25 mL supercritical CO2 sample has a mass of 11.7g