3 years ago

5. Which numbers below are composite? 13 15 17 27 Help

Mathematics

1 answer:

yan [13]3 years ago

7 0

Answer:

15 and 27 are composite

Step-by-step explanation:

prime numbers only factor into 1(x) and x(1)

13 = 1(13), 13(1)

15 = 1(15), 3(5), 5(3), 15(1)

17 = 1(17), 17(1)

27 = 1(27), 3(9), 9(3), 27(1)

hope this helps

You might be interested in

Fill in the blank. In the triangle below, x =

Evgesh-ka [11]

Hello, i definitely don’t know i just need to answer something sorry

4 0

3 years ago

-2 = g - 9 solve equation

jekas [21]

OK. Hold on tight. Here we go.
Remember ... the "solution" is the number that 'g' must be
in order to make the equation a true statement.

The original equation: You said that -2 = g - 9

Now, let's add 9 to each side: 7 = g .

8 0

3 years ago

Read 2 more answers

Write the equation in standard form for the circle with center (0, -1) and radius 10.

BARSIC [14]

Answer:

x^2 + (y+1)^2 = 10^2

Step-by-step explanation:

Centre (p,q) = (0, -1)

radius, r = 10

General Equation of a circle

(x-p)^2 + (y-q)^2 = r^2

(x-0)^2 + (y- -1)^2 = 10^2

x^2 + (y+1)^2 = 10^2

7 0

3 years ago

Worth 12 Points, i spent 24

rewona [7]

Answer:

$\displaystyle m^{\frac{35}{12}}n^{-\frac{28}{15}}=\frac{m^{\frac{35}{12}}}{n^{\frac{28}{15}}}$

Step-by-step explanation:

The relevant rule of exponents is ...

(a^b·c^d)^e = a^(be)·c^(de)

Then ...

(m^(5/4)·n^(-4/5))^(7/3) = m^(5/4·7/3)·n^(-4/5·7/3)

= m^(35/12)·n^(-28/15)

Since you want positive rational exponents, you can write this as ...

= m^(35/12)/n^(28/15)

6 0

3 years ago

An instructor who taught two sections of engineering statistics last term, the first with 25 students and the second with 40, de

Pavlova-9 [17]

Answer:

the answer is b

Step-by-step explanation:

8 0

3 years ago