Step-by-step explanation:
put them in least to greatest, so that would be: 0,0,1,1,1,1,2,3,3,6,8,7,8, then do the greatest minus the lowest: 8-0=8
<span>So far I have:
(1.25 + 1) </span><span>if </span>x<span> is in the interval</span><span> (-inf,7]
(2.25 +1) </span><span>if </span>x<span> is in the interval (7,13)</span><span>
(3.50+1+3) </span><span>if </span>x<span> is in the interval [13,inf)</span>
10[(6 + 4) / 2]
10[10/2]
10 * 5
50 <==
Answer: i dont really know if im right but here! :L
Step-by-step explanation: Now, say G is an Abelian group, finitely generated from generator In this sense abelian groups are “more interesting” than vector spaces. and in the table below, the second last column is the identity, while the last column is cyclic of order 4, with 9g the generator
Answer:
D
Step-by-step explanation:
