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castortr0y [4]
3 years ago
12

Balance the chemical equation by indicating the number of each species in the appropriate blanks. For this exercise, indicate co

efficients of 1 explicitly. Match the numbers in the left column to the appropriate blanks in the chemical equations on the right. Make certain the chemical equation is complete before submitting your answer.
Chemistry
1 answer:
ch4aika [34]3 years ago
8 0

Answer:

3 Fe (s) + 4 H2O (l) -----> Fe3O4 (s) + 4 H2 (g)

Explanation:

your question is not completed , perhaps the question is similar to this solution, you can use it .

The balanced equation is

3 Fe (s) + 4 H2O (l) -----> Fe3O4 (s) + 4 H2 (g)

Explanation: In order to balance an equation we must ensure that the number of atoms of each species on right side of the arrow must be equal to the number of atoms of each species on left side of the arrow.

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Answer:

According to avogadro's law, 1 mole of every substance contains avogadro's number 6.023\times 10^{23} of particles and weighs equal to its molecular mass.

To calculate the moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}

\text{Number of moles}=\frac{\text{Given molecules}}{\text {Avogadros number}}

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molecules in 14.08 g of C_{12}H_{22}O_{11} = 0.04113\times 6.023\times 10^{23}=0.2477\times 10^{23}

b. moles in 17.75 g of NaCl = \frac{17.75g}{58.5g/mol}=0.3034moles

molecules in 17.75 g of NaCl = 0.3034\times 6.023\times 10^{23}=1.827\times 10^{23}

formula units 17.75 g of NaCl = 0.3034\times 6.023\times 10^{23}=1.827\times 10^{23}

c. moles in 20.06 g of  CuSO_4.5H_2O= \frac{20.06g}{249.68g/mol}=0.08034moles

formula units in 20.06 g of  CuSO_4.5H_2O= 0.08034\times 6.023\times 10^{23}=0.4839\times 10^{23}

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Explanation:

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