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Maslowich
3 years ago
5

so how many moles of Fe are in 3.10 mole of iron oxide FeO still waiting for answer please, my grandchild needs help that I can'

t give thank you
Chemistry
1 answer:
alisha [4.7K]3 years ago
7 0
The answer is 3.10 because it's still the same amount moles of iron.
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PLEASE HELP!!! I will mark brainliest I am really struggling with these problems
Ket [755]

Answer:

21883.75 Joules are required to melt the ice!

5 0
3 years ago
3k+aici3 3kci+ai is what type of reaction
exis [7]
3K      +     AlCl3 -------->  3 KCl     +          Al
element    compound     compound       element

This is single replacement (displacement) reaction.
3 0
2 years ago
If 5.57 g of Ag2O is sealed in a 75.0-mL tube filled with 760 torr of N2 gas at 28 ∘C, and the tube is heated to 310 ∘C, the Ag2
Snezhnost [94]

Answer: Total pressure = 7293.2 torr or 9.60 atm

Explanation:

<em>Total pressure = partial pressure of nitrogen + partial pressure of oxygen</em>

The partial pressure due to nitrogen is determined using the equation of Gay-Lussac's law: <em>P₁/T₁=P₂/T₂</em>

P₁ = 760 torr = 1atm, T₁ = 28∘C = (273+28)K = 301k, P₂ = ?, T₂ = 310∘C =(310+273)K = 583K

P₂ = P₁ T₂/ T₁

P₂ = 760 * 583 / 301 = 1472.03 torr

The pressure due to Oxygen gas produced is calculated thus:

Balanced equation of the decomposition of Ag₂O at s.t.p. is as follows;

2Ag₂O ----> 4Ag + O₂(g)

2 moles of Ag₂O produces 1 mole of O₂

molar mass of Ag₂O = (2*108 + 16)g = 232g/mol

molar volume of gas at s.t.p. = 22.4L

2*232g i.e. 464g of Ag₂O produces 22.4L of O₂

5.57g of Ag₂O will produce 5.57g*22.4L/464g = 0.269L or 269mL of O₂

Using the General gas equation  P₁V₁/T₁=P₂V₂/T₂

P₁ = 1atm = 760 torr, V₁ = 269mL, T₁=273K, P₂ = ?, V₂= 75mL, T₂ = 583K

P₂ = P₁V₁T₂/V₂T₁

P₂ = 760*269*583 / 75*273

P₂ = 5821.17 torr

Total pressure = (1472.03 + 5821.17) torr

Total pressure = 7293.2 torr or 9.60 atm

7 0
2 years ago
When a rock is wrapped in aluminum foil, the radiation detected from the 29
zalisa [80]

Answer:

gamma

Explanation:

5 0
3 years ago
How many moles of zinc, Zn, are in 1.31×1024 Zn atoms?
liubo4ka [24]

Answer:

=7.89013× 10^47 moles of zinc

Explanation:

1 atom contains 6.023×10^23 moles.

1.31×10^24 atoms of zinc contain6.023×10^24×1.31×10^.24

6 0
2 years ago
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