Answer:c. Hofmann's; less
Explanation:
The Hofmann elimination process, named after its discoverer, the German chemist August Wilhelm Von Hofmann rule states that the major alkene product is the <u>least substituted </u>and least stable product when it comes to asymmetrical amines. The Hofmann elimination can be illustrated in t e formation of “Hoffman” products in elimination reactions using a less common, LDA LiN[CH(CH3)2]2 Lithium Di-isopropyl Amide (LDA) usually with base potassium t-butoxide which will give rise to a less substituted alkene.
This reaction will follow Hofmann's_____ rule and will form the ___less______ substituted alkene.
Answer:
D: The bond is created by oppositely charged metal and nonmetal atoms.
Explanation:
An ionic metal basically involves a metal and a nonmetal in bonding. A metal is a cation with a + charge and a nonmetal is a anion with a - charge. I will give you an example. Magnesium Chloride is a ionic bond. This is because Magnesium is a metal with a +2 charge(so it is a cation). Chloride or Chlorine is a nonmetal because it has a -1 charge.(so it is a anion). The chemical formula for magnesium chloride is MgCl2.
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Answer:
two dots around each side.
Explanation:
Answer:Nothing, the photon just bounces off the surface.
Explanation:
According to Albert Einstein, a photoelectron can only be emitted from a metal surface when the energy of the incident photon is greater than the work function of the metal.
In the scenario described in the question, the work function of the metal is greater than the energy of the photon. Hence, the photon just bounces off the metal surface without emitting any electron.
Answer:
the energy of the third excited rotational state
Explanation:
Given that :
hydrogen chloride (HCl) molecule has an intermolecular separation of 127 pm
Assume the atomic isotopes that make up the molecule are hydrogen-1 (protium) and chlorine-35.
Thus; the reduced mass μ =
μ =
μ =
∵ 1 μ = 1.66 × 10⁻²⁷ kg
μ =
μ = 1.6139 × 10⁻²⁷ kg
The rotational level Energy can be expressed by the equation:
where ;
J = 3 ( i.e third excited state) &
We know that :
1 J =