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2 years ago

A man roller skates up a hill at 12.5 m/s but slows down, comes to a stop and then accelerates

Physics

1 answer:

Brums [2.3K]2 years ago

7 0

Answer:

-11 m

Explanation:

Given:

v₀ = 12.5 m/s

v = -13.7 m/s

t = 18.3 s

Find: Δx

Δx = ½ (v + v₀) t

Δx = ½ (-13.7 m/s + 12.5 m/s) (18.3 s)

Δx = -11 m

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$Mv_x=m_1v_1\\\Rightarrow v_x=\dfrac{m_1v_1}{M}\\\Rightarrow v_x=\dfrac{9.11\times 10^{−31}\times 5.7\times 10^7}{2.34\times 10^{-26}}\\\Rightarrow v_x=2219.10256\ m/s$

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$Mv_y=p_2\\\Rightarrow v_y=\dfrac{p_2}{M}\\\Rightarrow v_y=\dfrac{7.3\times 10^{-24}}{2.34\times 10^{-26}}\\\Rightarrow v_y=311.96581\ m/s$

The resultant velocity is

$R=\sqrt{v_x^2+v_y^2}\\\Rightarrow R=\sqrt{2219.10256^2+311.96581^2}\\\Rightarrow R=2240.92365\ m/s$

The recoil speed of the nucleus is 2240.92365 m/s

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