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Anna11 [10]
3 years ago
14

Which of the following equations are balanced correctly?

Physics
1 answer:
skad [1K]3 years ago
6 0

Answer:

It looks like A is the correct answer.

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Each year, an average person in the United States is exposed to a radiation level of _____.
Anna11 [10]

Answer:

The correct answer is 0,2 rems

Explanation:

People are exposed to natural sources of radiation all the time. According to recent estimates, the average person in the United States receives an effective dose of approximately 3 mSv per year of natural radiation, which is equivalent to 0.3 rems. This amount includes cosmic radiation from outer space and is average because it varies depending on the region people are in.

The amount of radiation for a chest x-ray of an adult (0.01 rems) is approximately equal to 10 days of natural radiation to which we are all exposed every day.

Have a nice day!

3 0
3 years ago
1) A plane lands on a runway with a speed of 125 m/s, moving east, and it slows to a stop in 13.0 s. What is the magnitude (in m
valentina_108 [34]

Answer: 1) a = 9.61m/s² pointing to west.

             2) (a) Δv = - 37.9km/s

                  (b) a = - 6.10⁷km/years

Explanation: Aceleration is the change in velocity over change in time.

1) For the plane:

a=\frac{\Delta v}{\Delta t}

a=\frac{125}{13}

a = 9.61m/s²

The plane is moving east, so velocity points in that direction. However, it is stopping at the time of 13s, so acceleration's direction is in the opposite direction. Therefore, acceleration points towards west.

2) Total change of velocity:

\Delta v = v_{f}-v_{i}

\Delta v = -17.1-(+20.8)

\Delta v= -37.9km/s

The interval is in years, so transforming seconds in years:

v = \frac{-37.9}{3.15.10^{-7}}

v=-12.03.10^{7}km/years

Calculating acceleration:

a=\frac{-12.03.10^{-7}}{2.01}

a=-6.10^{7}

Acceleration of an asteroid is a = -6.10⁷km/years .

5 0
3 years ago
What are three common clues that a chemical change has occurred
ddd [48]
The substance has changed, It dissolved, and it evaproted.
6 0
3 years ago
Derive an expression for the gravitational potential energy of a system consisting of Earth and a brick of mass m placed at Eart
Arlecino [84]

Answer:

The gravitational potential energy of a system is -3/2 (GmE)(m)/RE

Explanation:

Given

mE = Mass of Earth

RE = Radius of Earth

G = Gravitational Constant

Let p = The mass density of the earth is

p = M/(4/3πRE³)

p = 3M/4πRE³

Taking for instance,a very thin spherical shell in the earth;

Let r = radius

dr = thickness

Its volume is given by;

dV = 4πr²dr

Since mass = density* volume;

It's mass would be

dm = p * 4πr²dr

The gravitational potential at the center due would equal;

dV = -Gdm/r

Substitute (p * 4πr²dr) for dm

dV = -G(p * 4πr²dr)/r

dV = -G(p * 4πrdr)

The gravitational potential at the center of the earth would equal;

V = ∫dV

V = ∫ -G(p * 4πrdr) {RE,0}

V = -4πGp∫rdr {RE,0}

V = -4πGp (r²/2) {RE,0}

V = -4πGp{RE²/2)

V = -4Gπ * 3M/4πRE³ * RE²/2

V = -3/2 GmE/RE

The gravitational potential energy of the system of the earth and the brick at the center equals

U = Vm

U = -3/2 GmE/RE * m

U = -3/2 (GmE)(m)/RE

5 0
3 years ago
How do tires help to increase the friction between the tire and the road?
Ipatiy [6.2K]
The teeth and threads creates roughness that increases the friction between the tire and the road. 
5 0
3 years ago
Read 2 more answers
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