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2 years ago

Please Help! Will mark Brainliest! 100 Points!

2 answers:

8 0

Question 1 - A hand span

Question 2 - B loaf of bread and a pillow

Question 3 - B He should repeat the test with three additional batteries of varying voltages to demonstrate the reproducibility of results.

These questions are all about materials all materials are matter the first question I pick A because a hand span would be a good measuring tool when you are measuring wings like that the second question I pick B because density is how light a object is the third question I pick B because when you repeat the expierment you are adding in the results and making your solution stronger.

Your answers are A,B,and B.

Otrada [13]2 years ago

3 0

C.

A loaf of bread.

D.

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A natural atom can be negatively charged by

svet-max [94.6K]

Answer:

By Gaining Electrons

Explanation:

A nuetral atom is negative when it gains electrons, and it can be positive when it loses electrons.

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2 years ago

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A sewing machine uses 1.6kWh of electricity in one day. If electricity costs 9p per unit, what is the total cost in pence of usi

atroni [7]

Answer:

$\huge\boxed{\sf 1.6\ units = 14.4p}$

Explanation:

Since,

So,

1.6 kWh = 1.6 units

If,

1.6 units = 9p × 1.6

1.6 units = 14.4p

$\rule[225]{225}{2}$

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1 year ago

A 975-kg sports car (including driver) crosses the rounded top of a hill at determine (a) the normal force exerted by the road o

iVinArrow [24]

There are missing data in the text of the problem (found them on internet):
- speed of the car at the top of the hill: $v=15 m/s$
- radius of the hill: $r=100 m$

Solution:

(a) The car is moving by circular motion. There are two forces acting on the car: the weight of the car $W=mg$ (downwards) and the normal force N exerted by the road (upwards). The resultant of these two forces is equal to the centripetal force, $m \frac{v^2}{r}$ , so we can write:
$mg-N=m \frac{v^2}{r}$ (1)
By rearranging the equation and substituting the numbers, we find N:
$N=mg-m \frac{v^2}{r}=(975 kg)(9.81 m/s^2)-(975 kg) \frac{(15 m/s)^2}{100 m}=7371 N$

(b) The problem is exactly identical to step (a), but this time we have to use the mass of the driver instead of the mass of the car. Therefore, we find:
$N=mg-m \frac{v^2}{r}=(62 kg)(9.81 m/s^2)-(62 kg) \frac{(15 m/s)^2}{100 m}=469 N$

(c) To find the car speed at which the normal force is zero, we can just require N=0 in eq.(1). and the equation becomes:
$mg=m \frac{v^2}{r}$
from which we find
$v= \sqrt{gr}= \sqrt{(9.81 m/s^2)(100 m)}=31.3 m/s$

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3 years ago

Hufflepuff and Ravenclaw are having their annual tug of war contest. Each team can have 20 students. What is the most important

Troyanec [42]

It should be S since S stands for students. Giving the team with more members the upper hand. Hope this helps.

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3 years ago

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Why do electrons flow threw a wire

Zolol [24]

Answer:

When electric voltage is applied, an electric field within the metal triggers the movement of the electrons, making them shift from one end to another end of the conductor. Electrons will move toward the positive side.

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1 year ago