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ra1l [238]
3 years ago
8

Please help!! I dont understand this unit at all!!! WILL AWARD BRAINLIEST ANSWER

Physics
1 answer:
Rufina [12.5K]3 years ago
6 0

Your answer is D. 4



i hate the 20 word count


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Part C
ivanzaharov [21]

Answer:

the other colours get absorbed by the paper

3 0
3 years ago
Read 2 more answers
I need to know the correct answer please ?
mrs_skeptik [129]

Answer:

675 Pa.

Explanation:

F = 5+2cos(15t) kN

Area (a) = 8*10-3 m2

Now at t =4 sec

            F= 5+2cos(60)

             = 5+2*0.5

              = 6  kN

Now ,force efficiency is 90%.

Hence,the effectively transmitted force,

            Fe = 0.90*6

                = 5.4 kN

Hence,pressure is given as,

            P = Fe/a

                = 5.4*10^3/(8 *10^-3))

              P = 675 Pa....answer

6 0
4 years ago
A charge of +0.001 C is 1 m to your right and another charge of +1000 C is 1 m to your left. You are holding a charge of −1 C. W
almond37 [142]

Answer:

C and D

Explanation:

Charge on right = +0.001 C

Charge on left = 1000 C

Charge held in between = -1C

Ratio between right and left charge:

=\frac{1000}{.001}\\\\=1\times 10^6

Which shows charge on left exerts 1,000,000 times more force then charge on right

Charge on left is 1000 times greater in magnitude than charge held between and charge held between is 1000 times greater in magnitude than charge on right. So the magnitude of the force on the charge you are holding would be the same if it were +1 C instead of −1 C.

8 0
3 years ago
Shyla is carrying a 10 kg bag up the stairs. Jonas is holding a 15 kg bag. Who is doing more work and why?
solniwko [45]
Jonas because is bag is heavier
5 0
4 years ago
A 1200-kg SUV is moving alone a straight highway at 12.0 m/s. Another car, with mass 1800 kg and speed 20.0 m/s, has its center
andreev551 [17]

Answer:

A) d = 24 m

B) 50400 kg.m/s

C) v₀ = 16.8 m/s

D) 50400 kg.m/s. It's equal to the momentum found in part B.

Explanation:

We are given;

Mass of station wagon;m1 = 1200 kg Velocity; V = 12 m/s

Mass of car; m2 = 1800 kg

Velocity of car; v2 = 20 m/s

a ) Let centre of mass of car and station wagon be at a distance d from wagon

Thus,

If we take moment of weight about it, we have;

1200 x d = 1800 x ( 40 - d )

Where, d is the position of the center of mass of the system consisting of the two cars

Thus,

1200d = 72000 - 1800d

1200d + 1800d = 72000

3000 d = 72,000

d = 72,000/3000

d = 24 m

b ) Total momentum= m1•v1 + m2•v2

= (1200 x 12) + (1800 x 20)

= 14400 + 36000

= 50400 kg.m/s

c ) Let speed of centre of mass be v₀

Thus,

v₀ = (m1•v1 + m2•v2)/(m1 + m2)

v₀ = 50400/(1200 + 1800)

v₀ = 50400/3000

v₀ = 16.8 m/s

d) System Total momentum = velocity of centre mass x total mass

Thus,

Total momentum = v₀(m1 + m2)

= 16.8(3000) = 50400 kg.m/s .

This value is equal to what was calculated in part b

8 0
3 years ago
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