Find the value of x.

Can somebody please help me out:))

jeyben [28]

Answer:

50ft

Step-by-step explanation:

Hi,

Considering that one side is equal to 38 degrees, we know this isn't a 30 - 60 - 90 triangle.

One of the legs is equal to 40 feet

So, tan(b) = 40/x

tan(38 degrees) is 0.78 round up to 0.8 (if that's what your teacher wants)

0.8 = 40/x

0.8x = 40

x = 50ft

I hope this helps

8 0

3 years ago

What are three solutions to the equation -8y=-3x+16?

andreyandreev [35.5K]

The answer is <span>Slope = 0.750/2.000 = 0.375
x-intercept = 16/3 = 5.33333<span>
y-intercept = 16/-8 = 2/-1 = -2.00000 hope this helps</span></span>

8 0

3 years ago

Find the length of the third side. If necessary, round to the nearest tenth.

My name is Ann [436]

Answer:

7.8

Step-by-step explanation:

8 0

2 years ago

(c) Use a calculator to verify that Σ(x) = 64, Σ(x2) = 1118, Σ(y) = 628, Σ(y2) = 87,982, and Σ(x y) = 9,627.

amid [387]

The correlation based on the computation is 0.97.

<h3>How to compute the value?</h3>

It should be noted that the question is that we should simply calculate the correlation which is r.

The correlation will be:

= Σ(x y) / (Σ(x²) × Σ(y²)

= 9627/✓(1118 × 87982)

= 9627 ✓98363876

= 9627/9917.86

= 0.97

Learn more about computations on:

brainly.com/question/4658834

#SPJ1

7 0

1 year ago

Simplify the expression state any excluded values<br> 2a^2-4a+2<br> ---------------<br> 3a^2-3

chubhunter [2.5K]

Answer:

The simplified form is $\dfrac{2(x-1)}{3(x+1)}$ .

$x =1$ is the excluded value for the given expression.

Step-by-step explanation:

Given:

The expression given is:

$\dfrac{2a^2-4a+2}{3a^2-3}$

Let us simplify the numerator and denominator separately.

The numerator is given as $2a^2-4a+2$

2 is a common factor in all the three terms. So, we factor it out. This gives,

$=2(a^2-2a+1)$

Now, $a^2-2a+1=(a-1)(a-1)$

Therefore, the numerator becomes $2(a-1)(a-1)$

The denominator is given as: $3a^2-3$

Factoring out 3, we get

$3(a^2-1)$

Now, $a^2-1$ is of the form $a^2-b^2=(a-b)(a+b)$

So, $a^2-1=(a-1)(a+1)$

Therefore, the denominator becomes $3(a-1)(a+1)$

Now, the given expression is simplified to:

$\frac{2a^2-4a+2}{3a^2-3}=\frac{2(x-1)(x-1)}{3(x-1)(x+1)}$

There is $(x-1)$ in the numerator and denominator. We can cancel them only if $x\ne1$ as for $x=1$ , the given expression is undefined.

Now, cancelling the like terms considering $x\ne1$ , we get:

$\dfrac{2a^2-4a+2}{3a^2-3}=\dfrac{2(x-1)}{3(x+1)}$

Therefore, the simplified form is $\dfrac{2(x-1)}{3(x+1)}$

The simplification is true only if $x\ne1$ . So, $x =1$ is the excluded value for the given expression.

8 0

3 years ago