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Pepsi [2]
2 years ago
9

TRUE REMARIED

Mathematics
1 answer:
mr Goodwill [35]2 years ago
7 0

The domain and range of the new function compare to the domain and range of the original function is domain and range of the function will be same after the modification.

<h3>What is domain and range of the function?</h3>

The domain of a function is the set of values that we are allowed to plug into our function.

The range of a function is the set of values that the function assumes.

Given function:

f(x)= ab^{x}

As, the value increased by 2.

Now, the value of the given function f(x) is modified such that the value of b remains same but the value of a is increased by 2.

Here, The domain and range of the function will be same after the modification.

Learn more about this concept here:

brainly.com/question/12278642

#SPJ1

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(4x+___)+(2x+3)=6x+5<br> Find the missing term.
SOVA2 [1]

Answer:

(4x+2)+(2x+3)=6x+5

Step-by-step explanation:

(4x+___)+(2x+3)=6x+5

4x+2x=6x

5-3=?

5-3=2

2

7 0
2 years ago
Each of six jars contains the same number of candies. Alice moves half of the candies from the first jar to the second jar. Then
tino4ka555 [31]

Answer:

The number of candies in the sixth jar is 42.

Step-by-step explanation:

Assume that there are <em>x</em> number of candies in each of the six jars.

⇒ After Alice moves half of the candies from the first jar to the second jar, the number of candies in the second jar is:

\text{Number of candies in the 2nd jar}=x+\fracx}{2}=\frac{3}{2}x

⇒ After Boris moves half of the candies from the second jar to the third jar, the number of candies in the third jar is:

\text{Number of candies in the 3rd jar}=x+\frac{3x}{4}=\frac{7}{4}x

⇒ After Clara moves half of the candies from the third jar to the fourth jar, the number of candies in the fourth jar is:

\text{Number of candies in the 4th jar}=x+\frac{7x}{4}=\frac{15}{8}x

⇒ After Dara moves half of the candies from the fourth jar to the fifth jar, the number of candies in the fifth jar is:

\text{Number of candies in the 5th jar}=x+\frac{15x}{16}=\frac{31}{16}x

⇒ After Ed moves half of the candies from the fifth jar to the sixth jar, the number of candies in the sixth jar is:

\text{Number of candies in the 6th jar}=x+\frac{31x}{32}=\frac{63}{32}x

Now, it is provided that at the end, 30 candies are in the fourth jar.

Compute the value of <em>x</em> as follows:

\text{Number of candies in the 4th jar}=40\\\\\frac{15}{8}x=40\\\\x=\frac{40\times 8}{15}\\\\x=\frac{64}{3}

Compute the number of candies in the sixth jar as follows:

\text{Number of candies in the 6th jar}=\frac{63}{32}x\\

                                                    =\frac{63}{32}\times\frac{64}{3}\\\\=21\times2\\\\=42

Thus, the number of candies in the sixth jar is 42.

4 0
3 years ago
Ricky can ride 17 km on his bike in the same length of time ha can walk 9 km.if his riding speed is 4 kph faster than his walkin
aivan3 [116]
Distance=speed times time
if they take the same time, we cal the time , t

b=bike speed
w=walking speed

bikedistnace=17=bt
walkdistance=9=wt

b is 4 more than w
b=4+w

we have
17=bt
9=wt
b=4w

ok so
multiply first equation by 9 and 2nd by 17

153=9bt
153=17wt
set equal
9bt=17wt
divide both sides by t
9b=17w
sub b=4+w for b
9(4+w)=17w
distribute
36+9w=17w
minus 9w both sides
36=8w
divide both sides by 8
4.5=w

he walks 4.5kph
5 0
3 years ago
Solve 5h + 2(11 - h) = -5 (Find h. Explain each step please.)
pav-90 [236]

Answer:

h = -9

Step-by-step explanation:

Distribute the 2 to the parentheses:

5h + 2(11 - h) = -5

5h + 22 - 2h = -5

Add like terms:

3h + 22 = -5

3h = -27

h = -9

7 0
3 years ago
Read 2 more answers
Abiding by God's wisdom results in riches and honor, blessings, life, and God's favor.
ki77a [65]

Answer:

True kinda.  depends on beleif and culture

Step-by-step explanation:

6 0
2 years ago
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