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3 years ago

⚡️⚡️Really need help, would appreciate it⚡️⚡️

Mathematics

1 answer:

pentagon [3]3 years ago

3 0

Answer:

The answer to your question is letter A. Regular size is cheaper than Economy size by $0.0003 per gram

Step-by-step explanation:

Cost of 1 gr of economy size

5000 gr (5 kg) ------------------- $ 5.15

1 gr -------------------- X

x = 1 x 5.15 / 5000 = $0.0010

Cost of 1 gr of regular size

820 gr ------------------- $0.60

1 gr -------------------- x

x = 1 x 0.6 / 820 = $ 0.0007

Difference of cost = $0.0010 - $0.0007 = $0.0003

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Pleases show workkkkkkkkkkkkkkkk

melomori [17]

Answer:

5) 2(4 - n) = -3n

2 × 4 - 2 × n = -3n

8 - 2n = -3n

-2n + 3n = -8

1n = -8

n = -8/1

n = -8

6) 5 - 3(2 + 2w) = -7

5 - 3 × 2 + -3 × 2w = -7

5 - 6 - 6w = -7

-1 - 6w = -7

-6w = -7 + 1

-6w = -6

w = -6/-6

w = 1

7) 5(2r + 3) - 5 = 0

5 × 2r + 5 × 3 - 5 = 0

10r + 15 - 5 = 0

10r + 10 = 0

10r = -10

r = -10/10

r = -1

8) 3 - 5(2d - 3) = 4

3 - 5 × 2d - 5 × -3 = 4

3 - 10d + 15 = 4

-10d + 15 + 3 = 4

-10d + 18 = 4

-10d = 4 - 18

-10d = -14

d = -14/-10

d = 7/5

hope this helps you!!

7 0

3 years ago

A)-1 <br> B) 1<br> C) 2<br> D) -1/2

AURORKA [14]

Answer:

I believe it is C but then again I'm not sure good luck though

7 0

2 years ago

An elliptical-shaped path surrounds a garden, modeled by quantity x minus 20 end quantity squared over 169 plus quantity y minus

Margaret [11]

The <em>maximum</em> distance between any two points of the ellipse is 34 feet.

<h3>Procedure - Determination of the distance between two points of a ellipse</h3>

The maximum distance between any two points of a ellipse is the <em>maximum</em> distance between the ends of the ellipse along the <em>longest</em> axis, which is parallel to the y-axis in this case.

In addition, the equation of the ellipse in <em>standard</em> form is defined by this formula:

$\frac{(x-h)^{2}}{a^{2}} + \frac{(y-k)^{2}}{b^{2}} = 1$ (1)

Where:

$h, k$ - Coordinates of the center of the ellipse.
$a$ , $b$ - Lengths of each semiaxis.

Hence, the maximum distance ( $d_{max}$ ), in feet, is calculated by this formula:

$d_{max} = 2\cdot b$ (2)

If we know that $b = 17$ , then the maximum distance between any two points of the ellipse is:

$d_{max} = 2\cdot (17\,ft)$

$d_{max} = 34\,ft$

The <em>maximum</em> distance between any two points of the ellipse is 34 feet. $\blacksquare$

<h3>Remark</h3>

The statement is incomplete and poorly formatted, correct form is presented below:

<em>An elliptical-shaped path surrounds a garden, modeled by </em> $\frac{(x-20)^{2}}{169} + \frac{(y-18)^{2}}{289} = 1$ <em>, where all measurements are in feet. What is the maximum distance between any two points of the path.</em>

To learn more on ellipses, we kindly invite to check this verified question: brainly.com/question/19507943

5 0

2 years ago

Mind if I get some help?

Blababa [14]

(-3,-3) should be the coordinates

5 0

3 years ago

Express the work in terms of l, f, and θ. remember to use radians, not degrees, for any angles that appear in your answer.

ivolga24 [154]

Assuming I see a force F acting on an object at an angle theta with the horizontal pushing it through a rough surface over a distance L such that the horizontal component is just required to overcome friction.

Then work done is
W=FLcos(theta)

(Read assumptions above due to lack of diagram)

6 0

3 years ago