Three mole ratios can be written for a chemical reaction involving three substances
Q=mcT
125cal=(60.0g)(0.0920)(T-21)
[(125)/(60)(0.0920)]+21=T2
T2=43.6C
Answer:-
KOH determines how much Mg(OH)2 is made.
2 mol of Mg(OH)2 formed
Explanation:-
The balanced equation is
MgCl2 + 2KOH --> Mg(OH)2+ 2KCI,
From seeing the coefficients we notice
2 mol of KOH reacts with 1 mol of MgCl2
4 mol of KOH reacts with 1 x 4 / 2 = 2 mol of MgCl2
3 moles of MgCl2 was added but only 2 mol react.
So we see there is excess MgCl2 .
Hence KOH is the limiting reactant.
So KOH determines how much Mg(OH)2 is made.
We see from the balanced chemical equation,
2 mol of KOH gives 1 mol of Mg(OH)2.
4 mol of KOH will give 1 x 4 /2 = 2 mol of Mg(OH)2.
The answer is B) dry and irregular
You do not have to worry because it will not affect the yield of the pure crystals.
<h3>What is re-crystallization?</h3>
Re-crystallization is the process of obtaining pure crystals from a super saturated solution.
This is done by heating a solution of the impure substance to a high temperature and then allowing the hot solution to cool down and the crystals begin to appear.
You do not have to worry about sudden vigorous boiling of crystal solution when you add the second solvent to the solution because it will not affect the yield of the pure crystals.
Learn more about re-crystallization: brainly.com/question/10194206
