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spin [16.1K]
3 years ago
12

What is the percent Nitrogen in Mg(NO2)2?

Chemistry
1 answer:
shusha [124]3 years ago
7 0
Magnesium (Mg)=20.8957%
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Determine the molarity of a solution formed by dissolving 97.7 g libr in enough water to yield 750.0 ml of solution.
rewona [7]

Answer:

1.5 M.

Explanation:

  • Molarity (M) is defined as the no. of moles of solute dissolved in a 1.0 L of the solution.

<em>M = (no. of moles of LiBr)/(Volume of the solution (L).</em>

<em></em>

∵ no. of moles of LiBr = (mass/molar mass) of LiBr = (97.7 g)/(86.845 g/mol) = 1.125 mol.

Volume of the solution = 750.0 mL = 0.75 L.

∴ M = (no. of moles of luminol)/(Volume of the solution (L) = (1.125 mol)/(0.75 L) = 1.5 M.

3 0
4 years ago
Read 2 more answers
What is the area of triangle ABC with vertices A(x¹,y¹), B(x²,y²)and C (x³,y³)??????????<br>​
AlexFokin [52]

Answer:

Area = \frac{1}{2}|x_1(y_2 - y_3)+x_2(y_3 - y_1)+x_3(y_1 - y_2)|

Area = 2\ units^2

Explanation:

Given

A = (x_1,y_1)

B = (x_2,y_2)

C = (x_3,y_3)

Required

Determine the area

The area of a triangle is :

Area = \frac{1}{2}|A_x(B_y - C_y) + B_x(C_y - A_y) + C_x(A_y - B_y)|

By substituting values for the x and y coordinates of A, B and C;

We have:

Area = \frac{1}{2}|x_1(y_2 - y_3)+x_2(y_3 - y_1)+x_3(y_1 - y_2)|

So:

For instance

A = (0,3)

B= (2,1)

C = (2,3)

The area is:

Area = \frac{1}{2}|0(1-3) + 2(3-3) + 2(3-1)|

Area = \frac{1}{2}| 2*0 + 2*2|

Area = \frac{1}{2}| 0 + 4|

Area = \frac{1}{2}|4|

Area = \frac{1}{2} * 4

Area = 2\ units^2

7 0
3 years ago
For the gaseous reaction of carbon monoxide and chlorine to form phosgene (COCl₂):(b) Assuming that ΔS° and ΔH° change little wi
maksim [4K]

ΔG° at 450. K is -198.86kJ/mol

The following is the relationship between  ΔG°,  ΔH, and  ΔS°:

ΔH-T ΔS = ΔG

where  ΔG represents the common Gibbs free energy.

the enthalpy change,  ΔH

The temperature in kelvin is T.

Entropy change is  ΔS.

ΔG° = -206 kJ/mol

ΔH° equals -220 kJ/mol

T = 298 K

Using the formula, we obtain:

-220kJ/mol -T ΔS° = -206kJ/mol

220 kJ/mol +206 kJ/mol =T ΔS°.

-T ΔS = 14 kJ/mol

for ΔS-14/298

ΔS=0.047 kJ/mol.K

450K for the temperature Completing a formula with values

ΔG° = (450K)(-0.047kJ/mol)-220kJ/mol

ΔG° = -220 kJ/mol + 21.14 kJ/mol.

ΔG°=198.86 kJ/mol

Learn more about ΔG° here:

brainly.com/question/17214066

#SPJ4

7 0
2 years ago
PLEASE HELP WITH ENVI SCI QUESTION
Vladimir79 [104]
Different types of acid deposition are

sulphur dioxide
nitroges oxides
3 0
4 years ago
Convert 55.6 km to m <br> show equation
crimeas [40]

Explanation:

1 km = 1000m

55.6 km = x m

x = 55.6*1000

x = 55600m

5 0
3 years ago
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