Answer:
153.6771 amu
Explanation:
From the question given above, the following data were:
Isotope A:
Mass of A = 114.3789 amu
Abundance (A%) = 64.23%
Isotope B:
Mass of B =.?
Abundance (B%) = 100 – A%
Abundance (B%) = 100 – 64.23
Abundance (B%) = 35.77%
average atomic mass of Element Y = 128.4359 amu
The mass of the 2nd isotope (i.e isotope B) can be obtained as follow:
Average atomic mass = [(Mass of A × A%)/100] + [(Mass of B × B%)/100]
128.4359 = [(114.3789 × 64.23)/100] + [(Mass of B × 35.77) /100]
128.4359 = 73.4656 + (Mass of B × 0.3577)
Collect like terms
128.4359 – 73.4656 = Mass of B × 0.3577
54.9703 = Mass of B × 0.3577
Divide both side by 0.3577
Mass of B = 54.9703 / 0.3577
Mass of B = 153.6771 amu
Therefore, the mass of the 2nd isotope is 153.6771 amu
Answer:
The answer to your question is below
Explanation:
Alpha decay occurs when a radioactive atm emits an alpha particle (Helium atom).
a) ²⁵⁶Ra ⇒ ²⁵²₈₄ Po + ⁴₂He
b) ²¹⁹Rn ⇒ ²¹⁵₈₂Pb + ⁴₂He
c) ²¹¹Po ⇒ ²⁰⁷₈₀Hg + ⁴₂Hg
d) ²¹⁰Pb ⇒ ²⁰⁶₇₈Pt + ⁴₂Hg
e) ²³⁸U ⇒ ²³⁴₈₈U + ⁴₂Hg
Answer: Mass, Specific Heat and Temperature Change.
Explanation: Q=mcΔT
Q = heat energy (Joules, J)
m = mass of a substance (kg)
c = specific heat (J/kg∙K)
∆ is a symbol meaning "the change in"
∆T = change in temperature (Kelvins, K)
The safest method for diluting
concentrated sulfuric acid with water is to add acid to water. This way, when
spill occurs, the acid is already diluted and less harmful than adding water to
acid.
