3/8 of a lap is 1/32 of the entire race.
x - the number of laps in the race
![\frac{3}{8}=\frac{1}{32}x \\ \frac{3}{8} \times 32=x \\ 3 \times 4=x \\ x=12](https://tex.z-dn.net/?f=%5Cfrac%7B3%7D%7B8%7D%3D%5Cfrac%7B1%7D%7B32%7Dx%20%5C%5C%0A%5Cfrac%7B3%7D%7B8%7D%20%5Ctimes%2032%3Dx%20%5C%5C%0A3%20%5Ctimes%204%3Dx%20%5C%5C%0Ax%3D12)
There were 12 laps in the race.
Answer:
The solution for the system of equations is
x=2,y=−2
Explanation:
4x−3y=14.....equation (1)
y=−3x+4.....equation (2)
Solving by substitution
Substituting equation 2 in equation 1
4x−3⋅(−3x+4)=14
4x+9x−12=14
13x=14+12
13x=26
x=2
Finding y by substituting x in equation 1
4x−3y=14
4⋅2−3y=14
8−3y=14
8−14=3y
3y=−6
y=−2
Answer:
it will take 3 yrs for the value of camera to reach $162.
Step-by-step explanation:
<u>Pd</u><u> </u><u>=</u><u> </u><u>P</u><u>(</u><u>1</u><u>-</u><u>R</u><u>/</u><u>1</u><u>0</u><u>0</u><u>)</u><u>^</u><u>T</u>
<u>1</u><u>6</u><u>2</u><u> </u><u>=</u><u> </u><u>3</u><u>8</u><u>4</u><u>(</u><u>1</u><u>-</u><u>2</u><u>5</u><u>/</u><u>1</u><u>0</u><u>0</u><u>)</u><u>^</u><u>T</u>
<u>1</u><u>6</u><u>2</u><u>/</u><u>3</u><u>8</u><u>4</u><u> </u><u> </u><u>=</u><u> </u><u> </u><u>(</u><u>3</u><u>/</u><u>4</u><u>)</u><u>^</u><u>T</u>
<u>2</u><u>7</u><u>/</u><u>6</u><u>4</u><u> </u><u> </u><u>=</u><u> </u><u> </u><u>(</u><u>3</u><u>/</u><u>4</u><u>)</u><u>^</u><u>T</u>
<u>(</u><u>3</u><u>/</u><u>4</u><u>)</u><u>^</u><u>3</u><u> </u><u>=</u><u> </u><u> </u><u>(</u><u>3</u><u>/</u><u>4</u><u>)</u><u>^</u><u>T</u>
<u>T</u><u> </u><u>=</u><u> </u><u>3</u>
$96(2 payments) = $192
$192/(12 months) = $16 per month (she should set aside)