Answer:
2, 5, 9, 19
Step-by-step explanation:
Using the recursive formula f(n) = 2f(n - 2) + f(n - 1)
with f(1) = 2 and f(2) = 5
f(3) = 2f(3 - 2) + f(3 - 1)
= 2f(1) + f(2) = (2 × 2) + 5 = 4 + 5 = 9
f(4) = 2f(4 - 2) + f(4 - 1)
= 2f(2) + f(3) = (2 × 5) + 9 = 10 + 9 = 19
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Answer:
yes
Step-by-step explanation:
...
These tables have infinitely many values, but the simplest ones would be:
a) x|y
3|5
6|10
9|15
b) x|y
2|1
4|2
6|3
Your graph for c would look like the attached picture