Answer:
0.3898 = 38.98% probability that there will be 4 failures
Step-by-step explanation:
A sequence of Bernoulli trials forms the binomial probability distribution.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.
In which 
is the number of different combinations of x objects from a set of n elements, given by the following formula.
And p is the probability of X happening.
Let the probability of success on a Bernoulli trial be 0.26.
This means that 
a. In five Bernoulli trials, what is the probability that there will be 4 failures?
Five trials means that 
4 failures, so 1 success, and we have to find P(X = 1).
0.3898 = 38.98% probability that there will be 4 failures
Answer:
-3
Step-by-step explanation:
-2(2x+5)-x=5(x+1) +15
distribute
-4x-10-x=5x+5+15
add common terms
-5x-10=5x+20
move common terms to the same sides
-30=10x
divide
x=-3
This problem involves the dot product.
You must provide all info for position vector m. Your (2,) is inadequate.
Supposing that the terminal point of vector m were (2,3), then
m dot n would equal 8, or 8 = 2*2+3*y. Then 8 = 4 + 3y, and 4 = 3y, and y =3/4.
Please type in the terminal point of vector m and then answer this question following the above example.
Answer: 8.375
Step-by-step explanation:
Add them together and turn them into a decimal, and you have ur answer!
n = 66
Step-by-step explanation:
you can make a proportion 3/99 = 2/x
99 * 2= 198
3 * x = 3x
so the equation would be 198 = 3x
than do 198 ÷ 3 on ur calculator
so x (or n in this context) would equal 66
