Dora calculated the mean absolute deviation for the data set 35, 16, 23, 42, and 19. Her work is shown below.
1 answer:
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We have that
N 11)
a) graph the equation y=x²-3x-10
using a graph tool
see the attached figure
b) Determine the roots of the equations
the roots of the equations are the values for y=0
x²-3x-10=0
x²-3x-10=(x+2)*(x-5)=0
the roots are
x1=-2
x2=5
see the attached figure problem 11
N 12) what is the value of x in the equation?
3x²=7x
3x²=7x-------> 3x²-7x=0--------> x*(3x-7)=0
x1=0
3x-7=0------> 3x=7------> x=7/3
the values of x are
x1=0
x2=7/3---> 2.33
see the attached figure problem 12
N 13) what is the value of x in the equation?
x²-5x=6----------> x²-5x-6=0
x²-5x-6=0-------> (x+1)*(x-6)=0
the values of x are
x1=-1
x2=6
N 14) what is the value of x in the equation?
2x²-5x=12--------> 2x²-5x-12=0
using a graph tool
see the attached figure problem N 14
2x²-5x-12=0----------> (x+3/2)*(x-4)=0
the values of x are
x1=-3/2
x2=4
N 11)
a) graph the equation y=x²-3x-10
using a graph tool
see the attached figure
b) Determine the roots of the equations
the roots of the equations are the values for y=0
x²-3x-10=0
x²-3x-10=(x+2)*(x-5)=0
the roots are
x1=-2
x2=5
see the attached figure problem 11
N 12) what is the value of x in the equation?
3x²=7x
3x²=7x-------> 3x²-7x=0--------> x*(3x-7)=0
x1=0
3x-7=0------> 3x=7------> x=7/3
the values of x are
x1=0
x2=7/3---> 2.33
see the attached figure problem 12
N 13) what is the value of x in the equation?
x²-5x=6----------> x²-5x-6=0
x²-5x-6=0-------> (x+1)*(x-6)=0
the values of x are
x1=-1
x2=6
N 14) what is the value of x in the equation?
2x²-5x=12--------> 2x²-5x-12=0
using a graph tool
see the attached figure problem N 14
2x²-5x-12=0----------> (x+3/2)*(x-4)=0
the values of x are
x1=-3/2
x2=4