p-6p+7=3(2p-3)-4(-10+4p
We move all terms to the left:
p-6p+7-(3(2p-3)-4(-10+4p)=0
We add all the numbers together, and all the variables
p-6p-(3(2p-3)-4(4p-10)+7=0
We add all the numbers together, and all the variables
-5p-(3(2p-3)-4(4p-10)+7=0
Answer:
-5
Step-by-step explanation:
Here,
t2-t1=20-25=-5
t3-t2=15-20=-5
t4-t3=10-15=-5
t5-t4=5-10=-5
Answer:
Step-by-step explanation:x
+
3
y
=
−
27
The question is an illustration of combination and there are 729 potential pass codes available
<h3>How to determine the number of potential pass codes?</h3>
The given parameters are
Symbols available = 9
Length of pass code = 3
From the question, we understand that a symbol may be entered any number of times.
This means that each of the 9 available symbols can be used three times
So, the number of potential pass codes is
Passcodes = 9 * 9 * 9
Evaluate the product
Passcodes = 729
Hence, there are 729 potential pass codes available
Read more about combination at:
brainly.com/question/11732255
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