The probability of the offspring of a heterozygous father and homzygous mother having five fingers is 50%.
<h3>How to calculate genotype of a cross?</h3>
According to this question, a gene coding for the number of fingers in humans is involved. The allele for six fingers (F) is the dominant trait while the allele for five fingers (f) is the recessive trait.
If a cross between a heterozygous father that posseses a genotype of Ff and a homzygous mother that posseses a genotype of ff, the following offsprings will be produced:
This shows that the probability of the offspring of a heterozygous father and homzygous mother having five fingers is ½ (50%).
Learn more about genotype at: brainly.com/question/12116830
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Answer:
A cell wall, A large central vacuole and Chloroplasts
The answer is 50km your wel
yeast uses glycolysis and alcohol fermentation to break down sugars in dough then it releases alcohol and carbon dioxide as waste and the carbon dioxide gas causes the bread to rise
Explanation:
c a mixture is the answer
