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yawa3891 [41]
2 years ago
15

2.

Chemistry
1 answer:
padilas [110]2 years ago
4 0
The element is P (Phosphorus) and the atomic number is just the number of protons so for A it would be 15.

For B to find the atomic mass you would just have to add the protons and neutrons so 15+16=31 and as we can see Phosphorus does have a mass of 31 so for B it would be 31

For C it would be 5
And for D it would be the atomic mass of Phosphorus which is 31 over the atomic number which is 15 so it would be P31/15

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Answer:

The order of reaction is 2.

Rate constant is 0.0328 (M s)⁻¹

Explanation:

The rate of a reaction is inversely proportional to the time taken for the reaction.

As we are decreasing the concentration of the reactant the half life is increasing.

a) For zero order reaction: the half life is directly proportional to initial concentration of reactant

b) for first order reaction: the half life is independent of the initial concentration.

c) higher order reaction: The relation between half life and rate of reaction is:

Rate = \frac{1}{k[A_{0}]^{(n-1)}}

Half life =K\frac{1}{[A_{0}]^{(n-1)} }

\frac{(halflife_{1})}{(halflife_{2})}=\frac{[A_{2}]^{(n-1)}}{[A_{1}]^{(n-1)} }

where n = order of reaction

Putting values

\frac{109}{231}=\frac{[0.132]^{(n-1)}}{[0.280]^{(n-1)}}

0.472=(0.472)^{(n-1)}

Hence n = 2

halflife=\frac{1}{k[A_{0}]}

Putting values

231=\frac{1}{K(0.132)}

K = 0.0328

4 0
3 years ago
A newly discovered element, Z, has two naturally occurring isotopes. 90.3 percent of the sample is an isotope with a mass of 267
blsea [12.9K]
atomic mass=percentage of isotope a * mass of  isotope a + percentage of isotope b * mass of  isotope b+...+percentage of isotope n * mass of isotope n.

Data:
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percentage of isotope₁=90.3%

mass of isotope₂=270.9 u
percentage of isotope₂=9.7%

Therefore:

atomic mass=(0.903)(267.8 u)+(0.097)(270.9 u)=
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8 0
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Tanya [424]

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<h3>Further explanation</h3>

Given

Fluorine-18

Oxygen-18

Required

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Solution

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The principle used is the sum of the atomic number and mass number before and after the decay reaction is the same

The reaction

₈O¹⁸ + ₁¹H(proton) ⇒ ₉F¹⁸ + ₀n¹(neutron) + ₀γ⁰ (gamma)

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