The recursive formula is f(n+1)= f(n)-5.
Given sequence :
f(1)= 6, n≥1.
Let f(n) denote the nth term of the given sequence.
f(1)= 6
f(2)= 1 = f(1)-5
f(3)= -4 = 1-5= f(2) -5
f(4)= -9 = 1-10 = f(2)-10
and so on
Hence, the recursive formula is f(n+1)= f(n)-5.
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We need to find the remainder- the sticker left over
Divide 23 stickers into 4 piles = 23/4= 5 stickers per pile and 3 stickers left over
D. She would have 3 stickers left over
2−1+22+2=32125
Step-by-step explanation:
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Answer:
w=32
w/4 = 8
4/1 * w/4 = 8*4