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2 years ago

REAL-WORLD Classify Reactions in Real-World Scenarios

Chemistry

1 answer:

pishuonlain [190]2 years ago

5 0

The coefficients that will balance the tarnishing reaction equation are: 2, 1, 1,1

What is a chemical equation

Chemical equations are representations of chemical reactions using symbols and formula of the reactants and products.

The reactants are located on the left side while the products are located on the right side.

Reactants —> Products

The balancing of chemical equations follows the law of conservation of matter which states that matter can neither be created nor destroyed during a chemical reaction but can be transferred from one form to another.

Thus, we can obtain the coefficients that will balance the tarnishing reaction equation by simply balancing the equation:

How to balance the equation

Ag(s) + H₂S(g) → Ag₂S(s) + H₂(g)

There are 2 atoms of Ag on the right side and 1 atom on the left side. It can be balanced by writing 2 before Ag as shown below:

2Ag(s) + H₂S(g) → Ag₂S(s) + H₂(g)

Thus, the equation is balanced.

The coefficients are: 2, 1, 1, 1 :)

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Can someone balance these equations?

wolverine [178]

This is mind numbing, but I got you.

3NaOH + 1FeCl<em>3</em> = 1Fe(OH)<em>3 </em>+ 3NaCl

3Mg + 2H<em>3</em>(PO)<em>4</em> = 1Mg(PO<em>4</em>)<em>2</em> + 3H<em>2</em>

3 0

3 years ago

A methane molecule, CH4, in the stratosphere or (2) a CH3 molecule and a hydrogen atom formed from breaking one of the carbon‐hy

MA_775_DIABLO [31]

The methane molecule in the stratosphere has a higher potential energy than the CH₃ molecule and the hydrogen atom formed from breaking one of the carbon‐hydrogen bonds in a CH₄ molecule.

The complete question is:

<em>For each of the following situations, you are asked which of two objects or substances has the higher energy. Explain your answer with reference to the capacity of each to do work and say whether the energy that distinguishes them is kinetic energy or potential energy.</em>

<em>a. (1) A methane molecule, CH4, in the stratosphere or (2) a CH3 molecule and a hydrogen atom formed from breaking one of the carbon-hydrogen bonds in a CH4 molecule.</em>

<h3>Which have a higher energy?</h3>

The methane molecule in the stratosphere is a stable molecule and possesses chemical potential energy.

The CH₃ molecule and the hydrogen atom formed from breaking one of the carbon‐hydrogen bonds in a CH₄ molecule are unstable molecules and possesses kinetic energy. However, some of their energy has been used in breaking the bond.

Thus, the methane molecule in the stratosphere has a higher potential energy than the CH₃ molecule and the hydrogen atom formed from breaking one of the carbon‐hydrogen bonds in a CH₄ molecule.

In conclusion, the energy in the methane molecule is higher.

Learn more about potential energy at: brainly.com/question/14427111

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5 0

2 years ago

3.5g of a Certain compound X, known to be made of carbon, hydrogen, and perhaps oxygen, and to have a molecular molar mass of 15

shutvik [7]

Answer:

C₅H₁₀O₅

Explanation:

1. Calculate the mass of each element in 2.78 mg of X.

(a) Mass of C

$\text{Mass of C} = \text{5.13 g CO}_{2}\times \dfrac{\text{12.01 g C}}{\text{44.01 g }\text{CO}_{2}}= \text{1.400 g C}$

(b) Mass of H

$\text{Mass of H} = \text{2.10 g H$_{2}$O}\times \dfrac{\text{2.016 g H}}{\text{18.02 g H$_{2}$O}} = \text{0.2349 g H}$

(c) Mass of O

Mass of O = 3.5 - 1.400 - 0.2349 = 1.87 g

2. Calculate the moles of each element

$\text{Moles of C = 1400 mg C}\times\dfrac{\text{1 mmol C}}{\text{12.01 mg C }} = \text{116.6 mmol C}\\\\\text{Moles of H = 234.9 mg H} \times \dfrac{\text{1 mmol H}}{\text{1.008 mg H}} = \text{233.1 mmol H}\\\\\text{Moles of O = 1870 mg O} \times \dfrac{\text{1 mmol O}}{\text{16.00 mg O}} = \text{116 mmol O}$

3. Calculate the molar ratios

Divide all moles by the smallest number of moles.

$\text{C: } \dfrac{116.6}{116.6}= 1\\\\\text{H: } \dfrac{233.1}{116.6} = 1.999\\\\\text{O: } \dfrac{116}{116.6} = 1.00$

4. Round the ratios to the nearest integer

C:H:O = 1:2:1

5. Write the empirical formula

The empirical formula is CH₂O.

6. Calculate the molecular formula.

EF Mass = (12.01 + 2.016 + 16.00) u = 30.03 u

The molecular formula is an integral multiple of the empirical formula.

MF = (EF)ₙ

$n = \dfrac{\text{MF Mass}}{\text{EF Mass }} = \dfrac{\text{150 u}}{\text{30.03 u}} = 5.00 \approx 5$

MF = (CH₂O)₅ = C₅H₁₀O₅

The molecular formula of X is C₅H₁₀O₅.

8 0

4 years ago

Compounds containing chlorine have long been used to disinfect the water in swimming pools, but in recent years a compound of a

VLD [36.1K]

Explanation:

A period 4 element is one of the chemical elements in the fourth row (or period) of the periodic table of the elements.

...

Period 4 element.

Hydrogen Rubidium

Strontium

Yttrium

Zirconium

Niobium

6 0

4 years ago

Show all work:

Serggg [28]

The equation of the reaction is;

Ca(OH)2(aq) + 2HCl(aq) ------> CaCl2(aq) + 2H2O(l)

<h3>What is neutralization?</h3>

The term neutralization has to do with the process in which an acid reacts with a base to form salt and water only. A neutralization reaction is known by the fact that water is obtained by the reaction of hydrogen and hydroxide ions.

The equation of the reaction is;

Ca(OH)2(aq) + 2HCl(aq) ------> CaCl2(aq) + 2H2O(l)

Learn more about neutralization:brainly.com/question/27891712

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5 0

2 years ago