<span>perpendicular to a uniform 1.50- magnetic field, as shown in the figure.
Part A
Calculate the net force which the magnetic field exerts on the coil.
ANSWER:
=0Correct
Part B
Calculate the torque which the magnetic field exerts on the coil.
ANSWER:
=0Correct
Part C
The coil is rotated through a 30.0 angle about the axis shown, the left side coming out of the plane of the figureand the right side going into the plane. Calculate the net force which the magnetic field now exerts on the coil.(
Hint:
In order to help visualize this 3-dimensional problem, make a careful drawing of the coil when viewedalong the rotation axis.)
ANSWER:
=0Correct
Part D
Calculate the torque which the magnetic field now exerts on the coil.
ANSWER:
=8.09Ă—10
â’2
Correct
Torque on a Current Loop in a Magnetic Field
Learning Goal:
To understand the origin of the torque on a current loop due to the magnetic forces on the current-carrying wires.This problem will show you how to calculate the torque on a magnetic dipole in a uniform magnetic field. We startwith a rectangular current loop, the shape of which allows us to calculate the Lorentz forces explicitly. Then wegeneralize our result. Even if you already know the general formula to solve this problem, you might find itinstructive to discover where it comes from
Part A
Find , the electric field inside the cube.
Hint A.1 Net force on charges in a conductor
Hint not displayed
Hint A.2 Find the magnetic force magnitude
Hint not displayed
Hint A.3 Find the magnetic force direction
Hint not displayed
Hint A.4 Determine the force due to the electric field
Hint not displayed
Express the electric field in terms of , , and unit vectors ( , , and/or ).
ANSWER:
=CorrectNow, instead of electrons, suppose that the free charges have
positive
charge . Examples include "holes" insemiconductors and positive ions in liquids, each of which act as "conductors" for their free charges.
Part B
If one replaces the conducting cube with one that has positive charge carriers, in what direction does the inducedelectric field point?
ANSWER:
CorrectThe direction of the electric field stays the same regardless of the sign of the charges that are free to move in theconductor.Mathematically, you can see that this must be true since the expression you derived for the electric field isindependent of .Physically, this is because the force due to the magnetic field changes sign as well and causes positive charges tomove in the direction (as opposed to pushing negative charges in the direction). Therefore the result isalways the same: positive charges on the side and negative charges on the side. Because the electric fieldgoes from positive to negative charges will always point in the direction (given the original directions of</span>

Answer:

1.35×10¹² μg

Explanation:

Mass (Kg) = 1350 Kg

Mass (μg) =?

Thus, we can obtain the mass of the adult rhino in micrograms (μg) by converting 1350 Kg to microgram (μg) as follow:

1 Kg = 1×10⁹ μg

Therefore,

1350 Kg = 1350 kg / 1 kg × 1×10⁹ μg

1350 Kg = 1.35×10¹² μg

Therefore, 1350 Kg is equivalent to 1.35×10¹² μg.

It is important to **record **your **data **with all the decimals provided by the instruments even if they are **zero **because it increases the **accuracy **of the measurement.

<h3>What is accuracy in experimentation?</h3>

**Accuracy **refers to the ability to take correct measurement values during a specific **experiment** and/or **observational **procedure.

**Accuracy **is a fundamental issue in **data analysis** and helps to obtain conclusions from a given** experimental procedure.**

In conclusion, it is important to **record **your **data **with all the decimals provided by the instruments even if they are **zero **because it increases the **accuracy **of the measurement.

Learn more about **accuracy in experimentation** here:

brainly.com/question/23469197

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<span> </span>

Answer
is: volume is 20 mL.<span>

c</span>₁(CH₃COOH) = 2,5 M.<span>

c</span>₂(CH₃COOH) = 0,5 M.<span>

V</span>₂(CH₃COOH) = 100 mL.<span>

V</span>₁(CH₃COOH) = ?<span>

c</span>₁(CH₃COOH) · V₁(CH₃COOH)
= c₂(CH₃COOH) · V₂(CH₃COOH).<span>

2,5 M · V</span>₁(CH₃COOH)
= 0,5 M · 100 mL.<span>

V</span>₁(CH₃COOH) = 0,5 M · 100 mL ÷ 2,5 M.<span>

V</span>₁(CH₃COOH) = 20 mL ÷ 1000 mL/L =0,02 L.

There are six atoms of oxygen in that compound.