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3 years ago

In a chemical equation, what name does the left side have

Chemistry

2 answers:

Nesterboy [21]3 years ago

6 0

The reactants are on the left side

suter [353]3 years ago

3 0

On the left side would be your reactants and the right would be your products

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How a strontium salt emits colored light

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When excited electrons fall to lower energy levels, they can release energy in the form of light. metal ions in the salts used in the flame tests.

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3 years ago

During an experiment,what is the factor you are testing called

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the answer is variable

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3 years ago

Rules for naming ionic compounds wiht transition metal

Aneli [31]

Rules for naming ionic compounds with transition metal requires the elementary name of metal followed the anion name with suffix ide.

<h3>What are ionic compounds?</h3>

Ionic compounds are made up of ions, which are charged particles that occur when an atom (or group of atoms) acquires or loses electrons. Generally cations are metals and anions are non metals in it.

Following rules will be considered during naming:

First determine the metal's elemental name.

Give the nonmetal its elemental name and the suffix -ide.

Use roman numerals to denote positive charge when naming metals that can have distinct oxidation states.

Name the polyatomic ions according to their names.

Hence rules for naming are listed above.

To know more about nomenclature of ionic compounds, visit the below link:

brainly.com/question/18672152

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2 years ago

A gas has a volume of 4.25 m3 at a temperature of 95.0°C and a pressure of 1.05 atm. What temperature will the gas have at a pre

Goryan [66]

Answer:

$\boxed {\boxed {\sf 82.7 \textdegree C}}$

Explanation:

We are asked to find the temperature of a gas given a change in pressure and volume. We will use the Combined Gas Law, which combines 3 gas laws: Boyle's, Charles's, and Gay-Lussac's.

$\frac {P_1V_1}{T_1}=\frac{P_2V_2}{T_2}$

Initially, the gas has a pressure of 1.05 atmospheres, a volume of 4.25 cubic meters, and a temperature of 95.0 degrees Celsius.

$\frac {1.05 \ atm * 4.25 \ m^3}{95.0 \textdegree C}= \frac{P_2V_2}{T_2}$

Then, the pressure increases to 1.58 atmospheres and the volume decreases to 2.46 cubic meters.

$\frac {1.05 \ atm * 4.25 \ m^3}{95.0 \textdegree C}= \frac{1.58 \ atm *2.46 \ m^3}{T_2}$

We are solving for the new temperature, so we must isolate the variable T₂. Cross multiply. Multiply the first numerator by the second denominator, then multiply the first denominator by the second numerator.

$(1.05 \ atm * 4.25 \ m^3) * T_2 = (95.0 \textdegree C)*(1.58 \ atm * 2.46 \ m^3)$

Now the variable is being multiplied by (1.05 atm * 4.25 m³). The inverse operation of multiplication is division, so we divide both sides by this value.

$\frac {(1.05 \ atm * 4.25 \ m^3) * T_2}{(1.05 \ atm * 4.25 \ m^3)} = \frac{(95.0 \textdegree C)*(1.58 \ atm * 2.46 \ m^3)}{(1.05 \ atm * 4.25 \ m^3)}$

$T_2=\frac{(95.0 \textdegree C)*(1.58 \ atm * 2.46 \ m^3)}{(1.05 \ atm * 4.25 \ m^3)}$

The units of atmospheres and cubic meters cancel.

$T_2=\frac{(95.0 \textdegree C)*(1.58* 2.46 )}{(1.05 * 4.25 )}$

Solve inside the parentheses.

$T_2= \frac{(95.0 \textdegree C)*3.8868}{4.4625}$

$T_2= \frac{369.246}{4.4625} \textdegree C}$

$T_2 = 82.74420168 \textdegree C$

The original values of volume, temperature, and pressure all have 3 significant figures, so our answer must have the same. For the number we calculated, that is the tenths place. The 4 in the hundredth place to the right tells us to leave the 7 in the tenths place.

$T_2 \approx 82.7 \textdegree C$

The temperature is approximately <u>82.7 degrees Celsius.</u>

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3 years ago

The tendency of an object to resist change in its motion

spin [16.1K]

Inertia is the answer to this question

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3 years ago

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