Name the following ketone:

_are structures that allow for one-way blood flow through the heart HELP!!!!

seraphim [82]

Answer:

Ventricles

Explanation:

6 0

3 years ago

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Suppose of copper(II) acetate is dissolved in of a aqueous solution of sodium chromate. Calculate the final molarity of acetate

uranmaximum [27]

Answer:

0.0714 M for the given variables

Explanation:

The question is missing some data, but one of the original questions regarding this problem provides the following data:

Mass of copper(II) acetate: $m_{(AcO)_2Cu} = 0.972 g$

Volume of the sodium chromate solution: $V_{Na_2CrO_4} = 150.0 mL$

Molarity of the sodium chromate solution: $c_{Na_2CrO_4} = 0.0400 M$

Now, when copper(II) acetate reacts with sodium chromate, an insoluble copper(II) chromate is formed:

$(CH_3COO)_2Cu (aq) + Na_2CrO_4 (aq)\rightarrow 2 CH_3COONa (aq) + CuCrO_4 (s)$

Find moles of each reactant. or copper(II) acetate, divide its mass by the molar mass:

$n_{(AcO)_2Cu} = \frac{0.972 g}{181.63 g/mol} = 0.0053515 mol$

Moles of the sodium chromate solution would be found by multiplying its volume by molarity:

$n_{Na_2CrO_4} = 0.0400 M\cdot 0.1500 L = 0.00600 mol$

Find the limiting reactant. Notice that stoichiometry of this reaction is 1 : 1, so we can compare moles directly. Moles of copper(II) acetate are lower than moles of sodium chromate, so copper(II) acetate is our limiting reactant.

Write the net ionic equation for this reaction:

$Cu^{2+} (aq) + CrO_4^{2-} (aq)\rightarrow CuCrO_4 (s)$

Notice that acetate is the ion spectator. This means it doesn't react, its moles throughout reaction stay the same. We started with:

$n_{(AcO)_2Cu} = 0.0053515 mol$

According to stoichiometry, 1 unit of copper(II) acetate has 2 units of acetate, so moles of acetate are equal to:

$n_{AcO^-} = 2\cdot 0.0053515 mol = 0.010703 mol$

The total volume of this solution doesn't change, so dividing moles of acetate by this volume will yield the molarity of acetate:

$c_{AcO^-} = \frac{0.010703 mol}{0.1500 L} = 0.0714 M$

8 0

4 years ago

Which of the following questions will allow you to determine if a population of organisms are MOST LIKELY a result of natural or

Marysya12 [62]

Answer:c

Explanation:

8 0

3 years ago

If all the water in 430.0 mL of a 0.45 M NaCI solution evaporates what is the mass of NaCI will remain

skad [1K]

Answer:

11.31 g.

Explanation:

Molarity is defined as the no. of moles of a solute per 1.0 L of the solution.

M = (no. of moles of solute)/(V of the solution (L)).

∴ M = (mass/molar mass)of NaCl/(V of the solution (L)).

∴ mass of NaCl remained after evaporation of water = (M)(V of the solution (L))(molar mass) = (0.45 M)(0.43 L)(58.44 g/mol) = 11.31 g.

6 0

3 years ago

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What mass of melamine, c3n3(nh2)3, will be obtained from 113.0 kg of urea, co(nh2)2, if the yield of the overall reaction is 73.

creativ13 [48]

The balanced equation for the reaction is:

6 HNCO(l) → C3N3(NH2)3(l) + 3 CO2(g)

Convert amount of urea from kg to moles

Molar Mass of urea = 60.06 g/mol so, 113 kg urea contains

113 kg / 60.06 = 1.88 mol urea

From balanced equation 6 moles of urea yields only 1 melamine, so divide the moles of urea by 6.

1.88 / 6 = 0.313 kmol melamine

Now multiply 0.313 with molar mass of melamine that is 126 g/mol

126 x 0.313 = 39.438 kg

Yield of overall reaction is 73% so multiply 39.438 with 0.73

39.438 x 0.73 = 28.799 kg is the answer

6 0

3 years ago