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Maksim231197 [3]
2 years ago
6

James states that quadrilateral

Mathematics
1 answer:
mr_godi [17]2 years ago
3 0

Using the distance formula,

AD=\sqrt{(-1-3)^{2}+(-3-(-4))^{2}}=\sqrt{17}\\\\BC=\sqrt{(5-9)^{2}+(1-0)^{2}}=\sqrt{17} \\\\\therefore \overline{AD} \cong \overline{BC}

AB=\sqrt{(-1-5)^{2}+(-3-1)^{2}}=\sqrt{52}=2\sqrt{13}\\\\CD=\sqrt{(9-3)^{2}+(0-(-4))^{2}}=\sqrt{52}=2\sqrt{13}\\\\\therefore \overline{AB} \cong \overline{CD}

Since ABCD has two pairs of opposite congruent sides, it is a parallelogram.

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