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Molodets [167]
2 years ago
15

You plan to use a slingshot to launch a ball that has a mass of 0.025kg

Physics
1 answer:
Ann [662]2 years ago
4 0

From the calculations, the force required is 0.437 N.

<h3>What is force?</h3>

The term force is defined a the product of mass and acceleration. The force is required to move the sling the required distance.

If mass = 0.019 kg and acceleration =  23 m/s2 then we know that F = ma

It then follows that the required force is;

F = 0.019 kg  *  23 m/s2= 0.437 N

Missing parts

You plan to use a slingshot to launch a ball that has a mass of 0.019 kg. You want the ball to accelerate straight toward your target at 23 m/s2. How much force do you need to apply to the ball?

Learn more about force:brainly.com/question/13191643

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Question:<br>Define Force​
ArbitrLikvidat [17]

<em>Force</em><em> </em><em>is</em><em> </em><em>push</em><em> </em><em>or</em><em> </em><em>pull</em><em>.</em><em>.</em><em>.</em><em>.</em>

<em>thank</em><em> </em><em>you</em>

7 0
3 years ago
Use Poiseuille's Law to calculate the rate of flow in a small human artery where we can take η = 0.028, R = 0.008 cm, l = 2 cm,
FrozenT [24]

Answer:

1.435 x 10^-4 cm^3/s

Explanation:

coefficient of viscosity, η = 0.028 poise

Radius, R = 0.008 cm

length, l = 2 cm

Pressure, P = 5000 dyne/cm^2

The Poiseuille's formula is given below

V=\frac{\pi PR^{4}}{8\eta l}

Where, V is the rate of flow, that means volume flowing per second

V=\frac{3.14\times5000 \times {0.008}^{4}}{8 \times 0.028 \times 2}

V = 1.435 x 10^-4 cm^3/s

Thus, the rate of flow is 1.435 x 10^-4 cm^3/s.

8 0
4 years ago
astone is thrown upwards with an initial velocity of 25m/s at ange of 30 to the ground. work out the stones horizantal range?
Vadim26 [7]

Explanation:

R = \dfrac{v_0^2}{g}\sin{2\theta} = \dfrac{(25\:\text{m/s})^2}{9.8\:\text{m/s}^2}\sin{60°}

\:\:\:\:=55.2\:\text{m}

4 0
3 years ago
What reasoning is empirical in nature
nikdorinn [45]

Answer:

inductive reasoning

Explanation:

6 0
3 years ago
Read 2 more answers
How much force is needed to accelerate a 3kg book in 15m/s
kotegsom [21]
F=M×A
F=3 ×15
F=45N
so the force is 45 N
7 0
3 years ago
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