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miss Akunina [59]
3 years ago
8

How much force is needed to accelerate a 3kg book in 15m/s

Physics
1 answer:
kotegsom [21]3 years ago
7 0
F=M×A
F=3 ×15
F=45N
so the force is 45 N
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b)J= 1.515 x 10^{6 A/m²

c)V_{d =1.114 x 10^{4m/s

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radius 'r' = d/2 => 1.025 x 10^{-3 m

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a) the amount of electrons pass through the light bulb each second can be determined by:

I= Q/t

Q= I x t => 5 x 1

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where e is the charge of electron i.e 1.6 x 10^{-19C

n= Q/e => 5/ 1.6 x 10^{-19

n= 3.125 x 10^{19 electrons.

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J= 1.515 x 10^{6 A/m²

c) The typical speed'V_{d' of an electron is given by:

V_{d = \frac{J}{n|q|}

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V_{d =1.114 x 10^{4m/s

d) According to these equations,

J= I/A

V_{d = \frac{J}{n|q|} =\frac{I}{nA|q|}

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Also drift velocity will decrease as it is inversely proportional to the area

 

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