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andrew-mc [135]
3 years ago
11

A light, inextensible cord passes over a light, frictionless pulley with a radius of 15 cm. It has a(n) 12 kg mass on the left a

nd a(n) 4.1 kg mass on the right, both hanging freely. Initially their center of masses are a vertical distance 3.3 m apart. The acceleration of gravity is 9.8 m/s 2 . 3.3 m 15 cm ω 12 kg 4.1 kg At what rate are the two masses accelerating when they pass each other? Answer in units of m/s 2 .
Physics
1 answer:
Lerok [7]3 years ago
7 0

Answer:

5.04m/s^2

Explanation:

We define the variables like this,

m_1 = 15Kg

m_2 = 4.8Kg

g= 9.8m/s^2

a= Acceleration

We know that the rate  is gived for the equation,

a = \frac{F_{net}}{m_{Total}}

a= \frac{ ( m1 - m2 ) g}{ (m1 + m2 )}

a= \frac {10.2 ( 9.8 )}{19.8} = 5.04m/s^2

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I would like to know why this is the correct answer
kati45 [8]

Answer:

The correct answer is the ratio of net force to mass is constant across all objects.

3 0
3 years ago
What is the longest wavelength that can be observed in the third order for a transmission grating having 5200 slits/cm?
Anarel [89]

Answer:

641 nm.

Explanation:

Given that,

A transmission grating has 5200 slits/cm.

We need to find the longest wavelength that can be observed in the third order. Using grating equation as follows :

d\sin\theta=m\lambda ...(1)

d is slit spacing

No fo slit per unit length :

N={5200}\ slit/cm\\\\=520000\ slits/m

We know that, N = 1/d

For longest wavelength, θ = 90°

From equation (1)

\dfrac{\sin\theta}{m\lambda}=\dfrac{1}{d}\\\\520000=\dfrac{\sin(90)}{3\lambda}\\\\\lambda=\dfrac{1}{520000\times 3}\\\\=6.41\times 10^{-7}\ m\\\\=641\ nm

Hence, the longest wavelength in third order for a transmission grating is 641 nm.

3 0
3 years ago
When mantle rocks near the radioactive core are heated, they become less dense than the cooler, upper mantle rocks. These warmer
avanturin [10]
C.convection cells is the right answer
4 0
3 years ago
Read 2 more answers
At which point is the water table closest to the surface? Explain.
dangina [55]

The point is the water table closest to the surface in valleys.

In areas of topographic relief, the water table generally follows the surface but tends to approach it in valleys and intersect the surface with streams and lakes. Closest to the surface is the vented zone where the interstices between the soil are filled with both air and water. Below this layer is a saturation zone where the gaps are filled with water.

The water table is the subsurface boundary between the soil surface and the area where groundwater saturates the space between sediment and rock fissures. At this boundary, water pressure equals atmospheric pressure. The top surface of the groundwater is the groundwater table. Beneath this surface, all pore spaces and cracks in sediments and rocks are completely filled and saturated with water. Groundwater occurs in these saturated layers known as saturation zones or water vapor zones.

Learn more about The water table here:-brainly.com/question/1362512

#SPJ1

7 0
2 years ago
A car moving in a straight line starts at x = 0 at t = 0 . It passes the point x = 30.0 m with a speed of 10.0 m/s at t = 3.00 s
Bogdan [553]

Answer:

a) v=20.3m/s

b) a=2.35m/s^2

Explanation:

From the exercise we know:

x_{1}=30m; v_{1}=10m/s; t_{1}=3s

x_{2}=375m; v_{2}=50m/s; t_{2}=20s

The formula for average velocity is:

v=\frac{x_{2}-x_{1}}{t_{2}-t_{1}}

a) v=\frac{375m-30m}{20s-3s}=20.3m/s

The formula for average acceleration is:

a=\frac{v_{2}-v_{1}}{t_{2}-t_{1}}

b) a=\frac{(50-10)m/s}{(20-3)s}=2.35m/s^2

4 0
3 years ago
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