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Elis [28]
4 years ago
6

Use Poiseuille's Law to calculate the rate of flow in a small human artery where we can take η = 0.028, R = 0.008 cm, l = 2 cm,

and P = 5000 dynes/cm2. (Round your answer to three significant figures.)
Physics
1 answer:
FrozenT [24]4 years ago
8 0

Answer:

1.435 x 10^-4 cm^3/s

Explanation:

coefficient of viscosity, η = 0.028 poise

Radius, R = 0.008 cm

length, l = 2 cm

Pressure, P = 5000 dyne/cm^2

The Poiseuille's formula is given below

V=\frac{\pi PR^{4}}{8\eta l}

Where, V is the rate of flow, that means volume flowing per second

V=\frac{3.14\times5000 \times {0.008}^{4}}{8 \times 0.028 \times 2}

V = 1.435 x 10^-4 cm^3/s

Thus, the rate of flow is 1.435 x 10^-4 cm^3/s.

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Which three metals are in the third period (row) of the periodic table?
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Sodium, magnesium, and aluminum! 
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A soccer player extends her lower leg in a kicking motion by exerting a force with the muscle above the knee in the front of her
lisabon 2012 [21]

Answer:

10.09 N

Explanation:

Analogously to Newton's second law, torque can be defined as:

\tau=I\alpha

Here, I is the moment of inertia and \alpha is the angular acceleration. We have:

\tau=(0.65kg*m^2)(29.5\frac{rad}{s^2})\\\tau=19.18N*m

Torque is the vector product of the position vector of the point at which the force is applied by the force vector:

\vec{\tau}=\vec{r}\times \vec{F}

Since the effective lever arm is perpendicular to the force, the angle between them is 90^\circ. The magnitud of this vector product is defined as:

\tau=rFsen\theta.

Solving for F and replacing the known values:

F=\frac{\tau}{rsen\theta}\\F=\frac{19.18N*m}{1.9m(sen90^\circ)}\\F=10.09N

8 0
3 years ago
6. What is the bulk modulus of oxygen if 32.0 g of oxygen occupies 22.4 L and the speed of sound in the oxygen is 317 m/s?
Arlecino [84]

Answer:

\boxed{\sf Bulk \ modulus \ of \ oxygen \approx 143.5 \ kPa}

Given:

Mass of oxygen (m) = 32.0 g = 0.032 kg

Volume occupied by oxygen (V) = 22.4 L = 0.0224 m³

Speed of sound in oxygen (v) = 317 m/s

To Find:

Bulk modulus of oxygen

Explanation:

\sf Density \ of \ oxygen \ (\rho) = \frac{m}{V}

\sf \implies Bulk \ modulus \ of \ oxygen \ (B) = v^{2} \rho

\sf \implies B = v^{2}  \times\frac{m}{V}

\sf \implies B  =  {(317)}^{2}  \times  \frac{0.032}{0.0224}

\sf \implies B  =  {(317)}^{2}  \times 1.428

\sf \implies B  = 100489 \times 1.428

\sf \implies B  = 143498.292 \: Pa

\sf \implies B   \approx 143.5 \: kPa

3 0
3 years ago
The free-body diagram of a crate is shown. What is the net force acting on the crate? 352 N to the left 176 N to the left 528 N
Umnica [9.8K]

As per given conditions there are two directions along which forces are acting

1. Net force along left direction is given as

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2. Net force towards right direction is given as

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F_{net} = F_{right} - F_{left}

F_{net} = 968 - 528

F_{net} = 440 N

so here net forces must be 440 N towards right

7 0
4 years ago
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