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3 years ago

I need help with homwork. (please) On topic of exponents. Show all work

Mathematics

2 answers:

STatiana [176]3 years ago

8 0

8:7 because 7x5 35 ok

Blizzard [7]3 years ago

5 0

Answer:

Step-by-step explanation:

5:28^25 I think

6:keep the base multiply exponents

7:no because you would multiply the bases and keep the exponent the same

8:7 because 7 x 5= 35

1: 2 and 3 for the second part of it 2 and 5

2:7^30

3:54^3

4:Yes they are just flipped

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A chef is going to use a mixture of two brands of Italian dressing the first brand contains contains 7% vinegar and the second b

Cerrena [4.2K]

Answer:

176 of 12% vinegar

44 of 7% vinegar

Step-by-step explanation:

Percentage vinegar required = 11%

Volume = 220 mL

First brand % = 7%

Second brand % = 12%

Let p = volume of 12% vinegar material

Mixture :

0.12p + 0.07(220 - p) = 220 * 0.11

0.12p + 15.4 - 0.07p = 24.2

0.05p = 8.8

p = 8.8 / 0.05

p = 176

176 of 12% vinegar and

220 - 176 = 44

44 of 7% vinegar

4 0

3 years ago

Find the slope and reduce of p=(3/4,1 1/4) q=(-1/2,-1)

sergij07 [2.7K]

$\bf \begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
% (a,b)
p&({{ \frac{3}{4}}}\quad ,&{{ \frac{1}{4}}})\quad 
% (c,d)
q&({{ -\frac{1}{2}}}\quad ,&{{ -1}})
\end{array}$

$\bf slope = {{ m}}= \cfrac{rise}{run} \implies 
\cfrac{{{ y_2}}-{{ y_1}}}{{{ x_2}}-{{ x_1}}}\implies \cfrac{-1-\frac{1}{4}}{-\frac{1}{2}-\frac{3}{4}}\quad \cfrac{\leftarrow LCD=4}{\leftarrow LCD=4}
\\\\\\
\cfrac{\frac{-4-1}{4}}{\frac{-2\cdot 1-3}{4}}\implies \cfrac{\frac{-5}{4}}{\frac{-5}{4}}\implies \cfrac{-5}{4}\cdot \cfrac{4}{-5}\implies 1$

7 0

3 years ago

Please help me with this

cupoosta [38]

Can you please write what the question is? I need to know what the category is to figure out which one does not belong.

5 0

3 years ago

The Wisconsin Dairy Association is interested in estimating the mean weekly consumption of milk for adults over the age of 18 in

Stolb23 [73]

Answer:

$ME = 1.653 *\frac{7.9}{\sqrt{300}}= \pm 0.75$

±0.75 ounce

Step-by-step explanation:

Assuming this complete question: The Wisconsin Dairy Association is interested in estimating the mean weekly consumption of milk for adults over the age of 18 in that state. To do this, they have selected a random sample of 300 people from the designated population. The following results were recorded: xbar=34.5 ounces, s=7.9 ounces Given this information, if the leaders wish to estimate the mean milk consumption with 90 percent confidence, what is the approximate margin of error in the estimate?

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X=34.5$ represent the sample mean

$\mu$ population mean (variable of interest)

s=7.9 represent the sample standard deviation

n=300 represent the sample size

Solution to the problem

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

In order to calculate the critical value $t_{\alpha/2}$ we need to find first the degrees of freedom, given by:

$df=n-1=300-1=299$

Since the Confidence is 0.90 or 90%, the value of $\alpha=0.1$ and $\alpha/2 =0.05$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.05,199)".And we see that $t_{\alpha/2}=1.653$