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To solve this question, you must use the formula: q=mc(change in temperature), where q is heat, m is mass, C is specific heat and temperature change is temperature change. The specific heat for ice is 2.1kJ/Kg x K (given). The change in temperature is 15 degrees Celsius (which you should change to kelvins so you can cancel out units), or 273 + 15 = 288K. The mass is 150 grams, which is 0.15 kg. Now, we can solve for q, heat. We will do this by substituting variables into the formula. After simplifying and cancelling out units, the answer we get is: 90.72kJ.
The formula C2H4 can be classified as both a molecular formula
and an empirical formula. The answer is number 4.
Given:
Q = 9.4 kJ/(kg-h), the heat production rate
c = 4.18 J/(g-K), the heat capacity
t = 2.5 h, amount of time
Note that
c = 4.18 J/(g-K) = 4180 J/(kg-K) = 4.18 kJ/kg-K)
Consider 1 kg of mass.
Then
Qt = cΔT
where ΔT is the increase in temperature (°K)
(1 kg)*(9.4 kJ/(kg-h))*(2.5 h) = (1 kg)*(4.18 kJ/(kg-K))*(ΔT K)
23.5 = 4.18 ΔT
ΔT = 23.5/4.18 = 5.622 K = 5.622 °C
Answer: 5.62 K (or 5.62 °C)
<span>q(rxn) = - [q(water)+q(bomb)]
q(rxn) = -{[ (1000g)(4.184)(5.0)] + [ (5.0)(0.10)]}
q(rxn) = - (20920 + 0.5)
Now we divide 3.5g
q(rxn)= - (20920)/(3.5g)
q(rxn) = 5977.14
And final answer, change is to Kilo joule unit
-q(rxn) = 5.23 KJ/unit</span>
