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1 year ago

What is the answer and how to do this?

Mathematics

1 answer:

zhenek [66]1 year ago

6 0

Answer:

Step-by-step explanation:

Given :

⇒ P (Sumit) = 1/2

⇒ P (Sujan) = 1/3

⇒ P (Rakesh) = 1/a

⇒ P (total) = 3/4

============================================================

Solving :

⇒ 1/2 × 1/3 × 1/a = 3/4

⇒ 1/6 × 1/a = 3/4

⇒ 2/12 × 1/a = 9/12

⇒ a = <u>9/2</u>

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How do you get a34 from a=-11+7n

marissa [1.9K]

Answer:

Step-by-step explanation:

34=-11+7A

We move all terms to the left:

34-(-11+7A)=0

We add all the numbers together, and all the variables

-(7A-11)+34=0

We get rid of parentheses

-7A+11+34=0

We add all the numbers together, and all the variables

-7A+45=0

We move all terms containing A to the left, all other terms to the right

-7A=-45

A=-45/-7

A=6+3/7

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3 years ago

A collection of 20 coins made up of only nickels, dimes, and quarters has a total value of $3.35. If the dimes were nickels, the

Kay [80]

Answer: The required number of quarters in the collection is 11.

Step-by-step explanation: Given that a collection of 20 coins made up of only nickels, dimes and quarters has a total value of $3.35.

If the dimes were nickels, the nickels were quarters and the quarters were dimes, the collection of coins would have a total value of $2.75.

We are to find the number of quarters in the collection.

Let x, y and z represents the number of nickels, dimes and quarters respectively in the collection.

We will be using the following values of nickels, dimes and quarters in form of dollar :

1 nickel = $ 0.05, 1 dime = $ 0.10 and 1 quarter = $0.25.

Then, according to the given information, we have

$x+y+z=20\\\\\Rightarrow x=20-y-z~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)\\\\0.05x+0.10y+0.25z=3.35\\\\\Rightarrow 5x+10y+25z=335\\\\\Rightarrow x+2y+5z=67~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(ii)\\\\0.05y+0.25x+0.10z=2.75\\\\\Rightarrow 5y+25x+10z=275\\\\\Rightarrow y+2z+5x=55~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(iii)$

Substituting the value of x from equation (i) in equations (ii) and (iii), we have

$(20-y-z)+2y+5z=67\\\\\Rightarrow y+4z=47\\\\\Rightarrow y=47-4z~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(iv)$

and

$y+2z+5(20-y-z)=55\\\\\Rightarrow -4y-3z=-45\\\\\Rightarrow y=\dfrac{45-3z}{4}~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(v)$

Comparing the values of y from equations (iv) and (v), we get

$47-4z=\dfrac{45-3z}{4}\\\\\Rightarrow 188-16z=45-3z\\\\\Rightarrow 16z-3z=188-45\\\\\Rightarrow 13z=143\\\\\Rightarrow z=\dfrac{143}{13}\\\\\Rightarrow z=11.$

Thus, the required number of quarters in the collection is 11.

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2 years ago

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Lorico [155]

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3 years ago

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Answer:

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Step-by-step explanation:

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2 years ago

What is the answer and how to do this?​

What is the answer and how to do this?