All categories

3 years ago

If two angles form a linear pair, then they are adjacent and __________.

Mathematics

2 answers:

77julia77 [94]3 years ago

6 0

The answer is C. Supplementary.

solmaris [256]3 years ago

5 0

If two angles form a linear pair , then they are adjacent and supplementary.

By forming a linear pair, they form a 180-degree angle. Supplementary is the two angles that together form a 180 degree angle

hope this helps

You might be interested in

Solve for indicated side. Round to the nearest hundredth.<br> Z=

Diano4ka-milaya [45]

Answer:

z ≈ 145.62

Step-by-step explanation:

using the sine ratio in the right triangle

sin18° = $\frac{opposite}{hypotenuse}$ = $\frac{45}{z}$ ( multiply both sides by z )

z × sin18° = 45 ( divide both sides by sin18° )

z = $\frac{45}{sin18}$ ≈ 145.62 ( to the nearest hundredth )

6 0

2 years ago

Solve for x: X-2/x=5

Nataliya [291]

Let me try all my best for this

Please , open the file

Download docx

7 0

3 years ago

Statistics - Please Help!!!<br> The question is in the screenshot.

arsen [322]

Answer: See the table below (attached image)

SSb = 2345
SSt = 5639
DFb = 5
DFw = 54
MSb = 469

=============================================================

Explanation:

I'll start at the right side of the table and work my way toward the left side.

I recommend you have a one way ANOVA formula sheet handy. Such a formula sheet should be located somewhere in the ANOVA chapter of your stats textbook, or toward the appendix section. There are various free online resources to search out as well.

On that formula sheet you should find that

(MSb)/(MSw) = F

where MSb and MSw are the mean squares between and within respectively.

We can find the value of MSb like so

(MSb)/(MSw) = F

MSb = F*MSw

MSb = 7.682*61

MSb = 468.602

This rounds to 469, so we'll go with MSb = 469. The reason I'm rounding is that I've done a similar problem in the past, and the computer system wanted me to round to the nearest whole number. Also, note how every value of the table given to us consists of whole numbers. Of course, your teacher may want you to keep the decimal value instead. So I would ask for clarification if possible.

Since we're going with MSb = 469, this means 469 goes in the last box of row 1.

-----------------------------------------------

Now go back to your reference sheet to locate this formula

MSw = (SSw)/(DFw)

Rearrange this formula to get

DFw = (SSw)/(MSw)

Now plug in the values we have from the table to find,

DFw = (SSw)/(MSw)

DFw = (3294)/(61)

DFw = 54 which goes in the box found in the second row.

-----------------------------------------------

Now recall that

DFb + DFw = df

where DFb is the degrees of freedom between and df is the total degrees of freedom, which in this case is 59.

Using the table and the value we found earlier, we can see that,

DFb = df - DFw

DFb = 59 - 54

DFb = 5 this goes in the second box of row one (ie above the 54).

-----------------------------------------------

Also on your formula sheet, you should see something like

MSb = (SSb)/(DFb)

where each lowercase 'b' stands for "between", and the other abbreviations are what were discussed earlier.

That formula rearranges into

SSb = (DFb)*(MSb)

Then we can use the values we calculated earlier to find

SSb = (DFb)*(MSb)

SSb = (5)*(469)

SSb = 2345 this goes in the first box of row one.

----------------------------------------------

Lastly, computing the total sum of squares (SSt) will simply involve us adding the two SSb and SSw values to get

SSt = SSb + SSw

SSt = 2345 + 3294

SSt = 5639 this goes in the box of row three.

----------------------------------------------

To summarize, we have these values to fill into the table

SSb = 2345
SSt = 5639
DFb = 5
DFw = 54
MSb = 469

where we have these abbreviations

SS = sum of squares
MS = mean square
DF = degrees of freedom
b = between
w = within

Check out the diagram below for the filled in values.

To summarize the formulas used, we basically have the template of

MS = (SS)/(DF)

for both between and within. And we also have the formula F = (MSb)/(MSw). So effectively, the values are found through various division formulas or rearrangements of such. I'm referring to working along any given row. For any given column, we add up the values to get the totals, though that of course does not apply to MS or F.

Admittedly, ANOVA tables and concepts can be confusing because there are a lot of variables and steps going on. But once you get used to it, it's not too bad if you can see how the patterns are emerging (the division and additions I was referring to earlier).

4 0

3 years ago

Name each polynomial by degree and number of terms .

laiz [17]

Answer:

Polynomials are classified according to their number of terms. 4x3 +3y + 3x2 has three terms, -12zy has 1 term, and 15 - x2 has two terms. As already mentioned, a polynomial with 1 term is a monomial. A polynomial with two terms is a binomial, and a polynomial with three terms is a trinomial.

5 0

2 years ago

Use Stokes' Theorem to evaluate C F · dr F(x, y, z) = xyi + yzj + zxk, C is the boundary of the part of the paraboloid z = 1 − x

Serggg [28]

I assume $C$ has counterclockwise orientation when viewed from above.

By Stokes' theorem,

$\displaystyle\int_C\vec F\cdot\mathrm d\vec r=\iint_S(\nabla\times\vec F)\cdot\mathrm d\vec S$

so we first compute the curl:

$\vec F(x,y,z)=xy\,\vec\imath+yz\,\vec\jmath+xz\,\vec k$

$\implies\nabla\times\vec F(x,y,z)=-y\,\vec\imath-z\,\vec\jmath-x\,\vec k$

Then parameterize $S$ by

$\vec r(u,v)=\cos u\sin v\,\vec\imath+\sin u\sin v\,\vec\jmath+\cos^2v\,\vec k$

where the $z$ -component is obtained from

$1-(\cos u\sin v)^2-(\sin u\sin v)^2=1-\sin^2v=\cos^2v$

with $0\le u\le\dfrac\pi2$ and $0\le v\le\dfrac\pi2$ .

Take the normal vector to $S$ to be

$\vec r_v\times\vec r_u=2\cos u\cos v\sin^2v\,\vec\imath+\sin u\sin v\sin(2v)\,\vec\jmath+\cos v\sin v\,\vec k$

Then the line integral is equal in value to the surface integral,

$\displaystyle\iint_S(\nabla\times\vec F)\cdot\mathrm d\vec S$

$=\displaystyle\int_0^{\pi/2}\int_0^{\pi/2}(-\sin u\sin v\,\vec\imath-\cos^2v\,\vec\jmath-\cos u\sin v\,\vec k)\cdot(\vec r_v\times\vec r_u)\,\mathrm du\,\mathrm dv$

$=\displaystyle-\int_0^{\pi/2}\int_0^{\pi/2}\cos v\sin^2v(\cos u+2\cos^2v\sin u+\sin(2u)\sin v)\,\mathrm du\,\mathrm dv=\boxed{-\frac{17}{20}}$

6 0

3 years ago