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Arlecino [84]
2 years ago
10

What is the range in interval notation of the function graphed below?

Mathematics
1 answer:
attashe74 [19]2 years ago
5 0

Answer:

Range tells you how high and low the graph of this parabola goes in the “y” (vertical) directions.

1. We can see that the parabola peaks on the y-axis at y = 4. That’s as HIGH as it goes.

2. We also see that both sides of the parabola descend to the level of y = -7. That’s as LOW as it is shown to go.

So putting these together, we say the Range is given by:

-7 <= y <= 3

AMBIGUITY WARNING:

Because the two branches of the parabola go fall right down to the edge of the picture boundary, it’s UNCLEAR whether the parabola truly stops at y = -7 or CONTINUES on (to negative infinity).

In THAT case, the RANGE simplifies to:

Y <= 4

Done.

Step-by-step explanation:

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hodyreva [135]
Yes, as potatoelord said, divide 48,484,848 and 2. 
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4 0
3 years ago
Answer the Follow: P (7 4) P (6 3)
mote1985 [20]

Answer:

Step-by-step explanation:

Using closest Wolfram|Alpha interpretation: P (7 4) P (6 3)

Assuming

"P"

is referring to prime numbers

|

Use as

instead

Input interpretation:

primes | between 28 and P(18)

Values:

2 | 3 | 5 | 7 | 11 | 13 | 17 | 19 | 23 (9 primes)

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3 years ago
Find The Missing Angle Measure <br>A. 34 <br>B. 90<br>C. 6<br>D. 23<br>please help me with this ​
padilas [110]
R + 114 + 32 = 180
r = 180 - 32 -114
r = 34
So the answer is A
6 0
3 years ago
Read 2 more answers
7) PG &amp; E have 12 linemen working Tuesdays in Placer County. They work in groups of 8. How many
BabaBlast [244]

Part A

Since order matters, we use the nPr permutation formula

We use n = 12 and r = 8

_{n}P_{r} = \frac{n!}{(n-r)!}\\\\_{12}P_{8} = \frac{12!}{(12-8)!}\\\\_{12}P_{8} = \frac{12!}{4!}\\\\_{12}P_{8} = \frac{12*11*10*9*8*7*6*5*4*3*2*1}{4*3*2*1}\\\\_{12}P_{8} = \frac{479,001,600}{24}\\\\_{12}P_{8} = 19,958,400\\\\

There are a little under 20 million different permutations.

<h3>Answer: 19,958,400</h3>

Side note: your teacher may not want you to type in the commas

============================================================

Part B

In this case, order doesn't matter. We could use the nCr combination formula like so.

_{n}C_{r} = \frac{n!}{r!(n-r)!}\\\\_{12}C_{8} = \frac{12!}{8!(12-8)!}\\\\_{12}C_{8} = \frac{12!}{4!}\\\\_{12}C_{8} = \frac{12*11*10*9*8!}{8!*4!}\\\\_{12}C_{8} = \frac{12*11*10*9}{4!} \ \text{ ... pair of 8! terms cancel}\\\\_{12}C_{8} = \frac{12*11*10*9}{4*3*2*1}\\\\_{12}C_{8} = \frac{11880}{24}\\\\_{12}C_{8} = 495\\\\

We have a much smaller number compared to last time because order isn't important. Consider a group of 3 people {A,B,C} and this group is identical to {C,B,A}. This idea applies to groups of any number.

-----------------

Another way we can compute the answer is to use the result from part A.

Recall that:

nCr = (nPr)/(r!)

If we know the permutation value, we simply divide by r! to get the combination value. In this case, we divide by r! = 8! = 8*7*6*5*4*3*2*1 = 40,320

So,

_{n}C_{r} = \frac{_{n}P_{r}}{r!}\\\\_{12}C_{8} = \frac{_{12}P_{8}}{8!}\\\\_{12}C_{8} = \frac{19,958,400}{40,320}\\\\_{12}C_{8} = 495\\\\

Not only is this shortcut fairly handy, but it's also interesting to see how the concepts of combinations and permutations connect to one another.

-----------------

<h3>Answer: 495</h3>
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3 years ago
Here are several function rules. Calculate the output for
kherson [118]

Answer: 6

Step-by-step explanation:

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